Solving PV & Tangent Line Equations in Calculus

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Homework Help Overview

The discussion revolves around two calculus problems: one involving the application of Boyle's Law to determine the rate of change of volume with respect to pressure, and the other concerning the equations of tangent lines to a parabola at a specific point.

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  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between pressure and volume using differentiation in the context of Boyle's Law. Others discuss the formulation of tangent lines to a parabola and the conditions for tangency, including the need to equate slopes and intersection points.

Discussion Status

Some participants have provided mathematical expressions and relationships relevant to the problems, while others are clarifying their understanding of the tangent line problem. There is an acknowledgment of previous errors in derivative calculations, indicating an ongoing refinement of reasoning.

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Participants are working within the constraints of homework assignments, which may limit the information available or the methods they can employ. There is a focus on ensuring correct interpretations of mathematical principles and relationships.

cscott
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PV = C (Boyle's Law)

At a certain instant, the volume is 480 cm^3, the pressure is 160 kPa, and the pressure is increasing at a rate of 15 kPa/min. At what rate is the volume decreasing at this instant?

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Find the equations of both lines that pass through the point (2, 3) and are tangent to the parabola y = x^2 + x.



I don't really know where to start with these...
 
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[tex]PV=C\Rightarrow\frac{d}{dt}(PV)=\frac{d}{dt}C\Rightarrow \frac{dP}{dt}V+P\frac{dV}{dt}=0[/tex]

then plug-in the known values of P,V, and dP/dt to solve for dV/dt.
 
Any line through (2, 3) can be written as y= m(x- 2)+ 3 for some m.

If (x,y) is a point where that line intersects the parabola y= x2+ x, then we must have m(x-2)+ 3= x2+ x. If, in addition, the line is tangent to the parabola there, we must have
m= 2x+ 1. Solve those two equations for x and m.

I've edited this: before I had m= 2x- 1. Obviously, the derivative of x2+ x is 2x+ 1, not 2x- 1.
 
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Thank you.
 

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