Solving Quartic Equation using Derivative

  • Thread starter Thread starter asd1249jf
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary

Homework Help Overview

The problem involves solving a quartic equation given by x^4 + 3x^3 - 7x^2 - 15x + 18 = 0. Participants are discussing the use of derivatives and factoring methods to find the roots of the equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the potential use of the first and second derivatives to find critical points and concavity, questioning their relevance to finding x-intercepts. There is mention of using Ferrari's method and the rational roots theorem, with some expressing skepticism about the practicality of these methods.

Discussion Status

Some participants have suggested factoring as a viable approach and have pointed out the rational roots theorem as a tool to identify potential roots. There is an ongoing exploration of different methods, with no explicit consensus on the best approach yet.

Contextual Notes

Participants note that the original poster is required to use derivation, which may limit their approach. There are also references to the challenges and complexities of using certain formulas, indicating a shared concern about the difficulty of solving quartic equations.

asd1249jf

Homework Statement


[itex] x^4 + 3x^3 - 7x^2 - 15x + 18 = 0[/itex]

Find x

Homework Equations



First Derivative?
Second Derivative?

The Attempt at a Solution



Normally, I'd use Ferrari's method to tackle this problem but I am required to use derivation to find the answer...

Where do I go from here? Do I use first derivative to find critical points? second derivative for concavity? I'm not sure what those will be helpful for though..
 
Physics news on Phys.org
l46kok said:

Homework Statement


[itex] x^4 + 3x^3 - 7x^2 - 15x + 18 = 0[/itex]

Find x


Homework Equations



First Derivative?
Second Derivative?
Neither. The derivatives give you information about the shape of the curve, but not about x intercepts. Try factoring. I found one root using synthetic division immediately.
l46kok said:

The Attempt at a Solution



Normally, I'd use Ferrari's method to tackle this problem but I am required to use derivation to find the answer...

Where do I go from here? Do I use first derivative to find critical points? second derivative for concavity? I'm not sure what those will be helpful for though..
 
Mark44 is right, of course. The trick is to try and factor it. To help with that guessing game you should look at the rational roots theorem. Any rational root must be an integer divisor of 18.
 
And if you have no luck with the rational root theorem...

http://planetmath.org/encyclopedia/QuarticFormula.html
 
Last edited by a moderator:
gb7nash said:
And if you have no luck with the rational root theorem...

http://planetmath.org/encyclopedia/QuarticFormula.html

That's the Ferrari formula i46kok was talking about in the first post. Have you EVER tried to use it in a practical problem? It's absolutely horrid. :) It may as well not even exist. And the cubic isn't much better. You were joking, right?
 
Last edited by a moderator:
Dick said:
That's the Ferrari formula i46kok was talking about in the first post. Have you EVER tried to use it in a practical problem? It's absolutely horrid. :) It may as well not even exist. And the cubic isn't much better. You were joking, right?

Yeah, it's a last ditch effort :smile: When I was taking algebra, my professor made us turn it into a depressed/reduced quartic, and manipulate it and solve it as shown on this page:

http://www.sosmath.com/algebra/factor/fac12/fac12.html

Now that's horrid. But yeah, both methods are atrocious. One little arithmetic mistake and you're screwed.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K