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eliassiguenza

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## Homework Statement

a uniform rod of length 4.0m of mass M is supported by a cable which is under tension T. The other end rests against as wall, where it is held by friction. The coefficient of static friction is 0.5. An additional mass M is hung from the rod at a distance x from the wall

## Homework Equations

Mgx + 2 Mg = 4T sinӨ

2Mg = (R/2) + T sin Ө

R = T cos Ө

## The Attempt at a Solution

Solve the above three equations simultaneously for Ө = 37 to obtain the minimum value of x in metres where the additional mass M may be hung without causing the rod to slip.

Answer is : x min = 2.8 m

how do you solve this ? I am totally lost :'( please help I have an exam on monday next week :'(