Solving Rotating Frame Problem: Need Help!

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SUMMARY

The discussion centers on the Rotating Frame Problem, specifically addressing the acceleration of mass m_a after the catch is removed in a non-inertial frame. The user asserts that the acceleration should equal ω²r_a, where ω represents angular velocity. The conversation highlights that when two equal masses, m_a and m_b, are connected by a rope and subjected to centrifugal forces, the net acceleration is zero when m_a equals m_b and the length l equals 2r_a.

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  • Understanding of non-inertial reference frames
  • Familiarity with angular velocity (ω) and its implications
  • Knowledge of centrifugal force and its effects on connected masses
  • Basic principles of classical mechanics
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aditya~
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i am facing problem in attempting the peoblem attached below

if i work in the non inertial frame (the rotating)

shouldn't the acceleration of m_a after the catch is removed

be simply =[tex]\omega[/tex]2ra

thanks in advance
 

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The masses are connected with a rope. The centrifugal forces on them work in opposite direction. If [itex]m_a = m_b[/itex] and [itex]l = 2 r_a[/itex] The acceleration is obviously 0.
 

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