Solving Rotational Motion: Max Speed on Spherical Hill

AI Thread Summary
To determine the maximum speed a motorcycle rider can achieve while remaining on a spherical hill with a radius of 12 meters, it is essential to analyze the forces acting on the rider at the top of the hill. The gravitational force must equal the centrifugal force for the rider to stay in contact with the surface, leading to the equation mg = mv²/r. Simplifying this equation reveals that the maximum speed cannot exceed 24 mph or 10.8 m/s. Understanding the balance of forces is crucial for solving problems related to rotational motion on curved surfaces. This analysis highlights the importance of gravitational and centrifugal forces in maintaining contact with the hill.
mxer101
Messages
3
Reaction score
0
rotational motion??

Homework Statement


A rider rides a motorcycle over a spherical hill with a radius of 12 meters. Show that the max speed cannot exceed 24mph or 10.8 m/s is he is to remain on the surface of the hill


Homework Equations





The Attempt at a Solution


I am not sure which equation to use!
 
Physics news on Phys.org
What are the forces acting on him when he is on the top of the hill?
 
What force keeps him touching the hill?
 
the force keeping him on the hill is gravity so would I use g=1/2 dt2?
 
If he is to remain on the surface of the hill, his weight must be equal to the centrifugal force acting on him due to his circular motion. Therefore mg = mv^2/r. Find the value of v.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Where on the hill does the projectile land?
Replies
9
Views
3K
What Speed Causes Weightlessness on a Circular Hill?
Replies
2
Views
3K
Calculating Forces on a Motorcycle Riding in a Transparent Sphere
Replies
5
Views
2K
Question about springs and rotational/translational energy
Replies
4
Views
1K
Rotational Motion of a bowling ball
Replies
5
Views
3K
Calculating Clicks: Spoke Card Oscillations and Rotational Motion
Replies
3
Views
2K
How high can it coast up the hill, if you neglect friction?
Replies
1
Views
4K
Sphere Rolling Down Hill into Projectile Motion
Replies
3
Views
2K
Minimum safe height for a roller coaster
Replies
10
Views
5K
What's the source of increase in rotational energy of carousel?
Replies
9
Views
2K

Hot Threads

Recent Insights

Back
Top