Solving the Electric Field of a Spherical Shell

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SUMMARY

The discussion focuses on calculating the electric field of a conducting spherical shell with a radius of 19 cm and a net charge of -8.15 μC. The electric field just outside the shell is determined using the formula E = k * (F/q), resulting in an electric field of 2.03 x 10^6 N/C directed radially outward. However, the electric field inside the shell is zero, which is a fundamental property of conductors in electrostatic equilibrium. The confusion arises from the sign of the charge, which does not affect the electric field inside the shell.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with Coulomb's law and the constant k (Coulomb's constant)
  • Knowledge of properties of conductors in electrostatic equilibrium
  • Basic algebra for solving equations
NEXT STEPS
  • Study the properties of electric fields in conductors
  • Learn about Gauss's law and its application to spherical symmetry
  • Explore the concept of electric field lines and their behavior around charged objects
  • Investigate the effects of charge distribution on electric fields
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric fields around charged conductors.

DrMcDreamy
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Homework Statement



This is a two part problem:

3- A conducting spherical shell of radius 19 cm carries a net charge of −8.15 μC uniformly distributed on its surface. Find the electric field at points just outside the shell. (Take the radially outward direction to be positive.) Answer in units of N/C.

Homework Equations



E = k\frac{F}{q}

The Attempt at a Solution



E=k\frac{8.15x10^-6 C}{(.19 m)^2}=
E= 2.03x10^6\frac{Nm}{C}

4- Find the electric field at points inside the shell. Answer in units of N/C.

I am not sure how to do this part.
 
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The answer I had gotten (2.03e6) is wrong. Why?
 
The charge is negative.
 
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