Solving the Impulse-Momentum Equation for a Coasting Car

[madahmad1]

Homework Statement

A coasting car with a mass of 1000 kg has a speed of 100 km/h down a 10
degree slope when the brakes are applied. if the car is slowed to a speed of 50
km/ h in 8s, compute using the impulse-momentum equation the average of the total braking force exerted by the road on all the tires during the period. Treat the car as a particle and neglect air resistance.

Homework Equations

The Attempt at a Solution

The impulse-momentum equation states that the sum of Forces F = mdv/dt
so we turn this equation into an integral and solve, I know that the answer is 3400 N but do not know how to get it. any help?

 

[misho]

For this, I'm going to take up the ramp to be the positive direction and down the ramp to be the negative direction.

Let F be the net force (this should end up being positive, since the initial velocity is negative, based on the definition above, and the car is slowing down).
Let f be the frictional force (should be positive, for the same reasons).

By drawing the FBD, you should see that:

$$F = f - mg \sin 10 ^\circ$$
OR:
$$f = F + mg \sin 10 ^\circ$$

Also, we know the average acceleration of the car, so we know F:

$$F = m \frac{dv}{dt} = ma = m \frac{ (- \frac{50}{3.6})-(-\frac{100}{3.6}) }{ 8 } = m \frac{50}{8*3.6}$$

The rest is pretty obvious (I got 3439 N, which I figure is close enough).

I'm not sure why you would want to integrate F = mdv/dt, since you're looking for a force.

Just out of curiosity, which form of Newton's 2nd law were you taught is called the "impulse-momentum equation"? It's the first time I've heard the term used.