Solving the Inequality (x-1) / (x+2) < 1: Step-by-Step Guide

[acronym]

I've tried squaring both sides, then moving the RHS to the LHS, then factorizing according to a²-b²=(a+b)(a-b).

I simplified, and got
((2x+1)/(x+2))((-3/(x+2)) < 0

Then there are 2 cases:
((2x+1)/(x+2)) < 0 and ((-3/(x+2)) > 0

or

((2x+1)/(x+2)) > 0 and ((-3/(x+2)) < 0

I'm not really sure how to go from here...
Please reply ASAP!

 

[zgozvrm]

No need to square.

Don't forget: |x| &lt; y[/tex], means \pm x &amp;lt; y[/tex]

 

[acronym]

thanks for telling me! now i see how much easier it is :)