Solving the Non-Linear ODE: Seeking Help

  • Thread starter Thread starter gizsim
  • Start date Start date
  • Tags Tags
    Non-linear Ode
gizsim
Messages
1
Reaction score
0
Hi.
In the course of trying to solve the field equations of a physical system, within some assumptions about its symetry, i managed to get a non-linear ODE involving only a single function of one variable, but still rather tough to handle :
In the equation, x=x(r) is the unknown function to find, and p0, p1, p2 are KNOWN algebraic functions of r (that i didn't take the time to write down here, but are not too complicated functions).

p0*(x''-x'²) + x'(x²+2x) (-/+) p1*x^4 + p2*x³ - p2*x² (+/-) p1*x = 0

Do you guys have any ideas of how i could manage to obtain any analytic solution for x(r)?
I can't find any help, because its not a categorized equation (Ricatti, Abell, ...)
Thank you so much for your help!
 
Physics news on Phys.org
There might not be an analytical solution for that PDE.
 
Are there any small parameters in the problem?

If for example p1/p0 << 1 and p2/p0 << 1 then you might be able to find a solution using regular perturbation theory.
 
How to solve a equation of this kind

T' = a*(T^4 - r^4) + b*(T^4 - s^4) + P*(1 - eta(T))

The above equation is driving me nuts... the 'eta' is a function of T(Temperature) and initial value of T is known.
Say at t = 0 T is 298
Need help! Please!
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top