Black Integra
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Hi guys.
I was trying to play with trig function and I finally ended up with this equation:
\sqrt{2}sin(\frac{\pi}{2}-d\theta)=1-dx
How can I determine a function \Theta(x) from that equation?
Please, can anyone help me?
I was trying to play with trig function and I finally ended up with this equation:
\sqrt{2}sin(\frac{\pi}{2}-d\theta)=1-dx
How can I determine a function \Theta(x) from that equation?
Please, can anyone help me?