- #1
suspenc3
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How would I go about solving this:
[tex]\int cos^2x tan^3xdx[/tex]..all i did so far ..
[tex]\int cos^2x tanx(tan^2x)[/tex]
[tex][[ \frac{1}{cosx}^2 -1] = tan^2x[/tex]
so...
[tex] \int cos^2x[[ \frac{1}{cosx}]^2-1]tanx[/tex]
is this right so far...now what?
[tex]\int cos^2x tan^3xdx[/tex]..all i did so far ..
[tex]\int cos^2x tanx(tan^2x)[/tex]
[tex][[ \frac{1}{cosx}^2 -1] = tan^2x[/tex]
so...
[tex] \int cos^2x[[ \frac{1}{cosx}]^2-1]tanx[/tex]
is this right so far...now what?
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