Solving Very Hard Integral g(x) - Joe

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SUMMARY

The discussion centers on solving the integral equation involving an unknown function g(x) and its relationship to a second-order differential equation. The equation presented is y'' + cy' + dy = g(t), with initial conditions y(0) = y0 and y'(0) = y'0. Key strategies include using Leibniz's rule for differentiation of integrals and evaluating y(0) and y'(0) to determine the constants c and d. The participant, Joe, seeks assistance in finding these parameters based on the provided equations.

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g(x) is a function of x that we do not know its form.


y(t) =(1/2) integral 0-->t [ sin(2t-2x)*g(x) ]dx

i tried to use integration by substitution and by parts
but the problem is that g(x) has an unknown form.

the actual problem is that

y" +cy' +dy = g(t) y(0) = y0 y'(0) = y'0

we are asked to find c,d,y0,y'0
knowing that y(t) is the solution of the second order differential equation.

i would appreciate your help.
Thanks,
Joe
 
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Evaluate y(0) to find y0.

Differentiate y and evaluate y'(0) to find y'0

Insert y' and y'' in your equation, and determine c and d from that.

Remember Leibniz' rule for differentiating an integral with variable limits!
 

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