Solving voltage gain in an non-ideal op amp.

Click For Summary

Discussion Overview

The discussion revolves around solving for the voltage gain and other parameters of a non-ideal operational amplifier (op amp) in an open-loop configuration. Participants explore the implications of the op amp's non-ideal characteristics, such as finite input and output resistances, while attempting to derive the voltage gain and other related values based on given parameters.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant proposes a method to find the voltage gain using the formula Vo = A(Vp-Vn) and assumes Vp = 0, leading to a calculation of Vn based on Vo and A.
  • Another participant questions the algebra used in the initial analysis and points out that the non-idealities of the op amp were not adequately incorporated, specifically the finite input and output resistances.
  • A later reply suggests that the internal resistances should be added to the circuit analysis, indicating a need for a more accurate model of the op amp.
  • Some participants express confusion about whether to include the internal resistances in their calculations and how to redraw the circuit accordingly.
  • One participant mentions a formula for closed circuit gain but is advised to first use a model that includes the specified input and output impedances of the op amp.
  • Another participant critiques the initial voltage at the negative input terminal (Vn) as being implausibly high and suggests redrawing the circuit with an ideal op amp before incorporating the non-ideal characteristics.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to incorporate the non-ideal characteristics of the op amp into their calculations. Multiple competing views on how to analyze the circuit remain present throughout the discussion.

Contextual Notes

Participants express uncertainty regarding the correct application of the op amp model, particularly in relation to the input and output resistances. There are unresolved questions about the implications of these non-idealities on the overall analysis and calculations.

lam58
Messages
26
Reaction score
0
Hello I'm a bit stuck on this.

The question states that the non ideal op amp (pictured below) in open loop conditions has an input resistance of 400kΩ, an output resistance of 2kΩ and a voltage gain of 500,000.

I then asks to find the voltage gain, the voltage at the negative input terminal and the input and output resistances when the supply voltage is 50mV. So for the first part finding the gain I assumed V at positive terminal (Vp) = 0.

Thus Vo = A(Vp-Vn) => Vn = Vo/A.

Also \frac{V_{s}-V_{n}}{R_{s}} = \frac{V_{n}-V{o}}{R_f}

Then using Vn = Vo/A

\frac{R_f}{R_s} (V_s + \frac{V_o}{A}) = V_o (\frac{-1}{A}-1)

\Rightarrow \frac{V_s}{V_o} + A = \frac{(-1/A)-1}{R_f/R_s}

\Rightarrow \frac{V_o}{V_s} = \frac{(R_f/R_s)}{(-1/A)-1} - \frac{1}{A}

Putting in the values given:

gain = \frac{320k/8k}{(1/500k)-1} - \frac{1}{500,000} = -39.999922

From this I got V_o = - 1.9999961, V_n = 49.76v

However, here I don't know if the above is correct and how to find the input and output resistances. Any help would be much appreciated. :)

EDIT Just realiased how to find input resistance and output resistances using my first equation.

Is the working above correct though?
 

Attachments

  • jtjt.jpg
    jtjt.jpg
    4 KB · Views: 631
Last edited:
Physics news on Phys.org
So for the first part finding the gain I assumed V at positive terminal (Vp) = 0.

Thus Vo = A(Vp-Vn) => Vn = Vo/A.
Check this algebra.

The rest of your analysis ignores the non-idealities of the OP-AMP, apart from its finite gain. You have assumed its input impedance is ∞ and that its output impedance is 0Ω, despite being told the figures to use. You must show these as resistances inside the OP-AMP triangle and incorporate them into your analysis.
 
NascentOxygen said:
Check this algebra.

The rest of your analysis ignores the non-idealities of the OP-AMP, apart from its finite gain. You have assumed its input impedance is ∞ and that its output impedance is 0Ω, despite being told the figures to use. You must show these as resistances inside the OP-AMP triangle and incorporate them into your analysis.

Ok I'm lost now. Do I need to add the internal resistances to Rs and Rf?
 
A google search will tell you everything you need. Search on "non-ideal op-amp analysis"
 
I have been.
 
NascentOxygen said:
A google search will tell you everything you need. Search on "non-ideal op-amp analysis"

To find the closed circuit gain would I do A = Aβ/(1+(Rf/Rs)) which would give me roughly 12.2k?
 
lam58 said:
To find the closed circuit gain would I do A = Aβ/(1+(Rf/Rs)) which would give me roughly 12.2k?
Not until you have used the model that shows the OP-AMP itself having those given figures for input impedance and output impedance. A google search will quickly find the non-ideal OP-AMP model.
 
lam58 said:
Hello I'm a bit stuck on this.

EDIT Just realiased how to find input resistance and output resistances using my first equation.

Is the working above correct though?

Not likely, since your v_n is way higher than the power supplies and the offset voltage of the op amp woud have to be equal to v_n !

What you want to do is redraw the circuit with an ideal op amp, then add the input and output resistances to the circuit. This will generate new nodes and more simultaneous equations to solve. Be careful how you place those resistances. When you do that you can send us the new schematic. BTW your image is hard to read.
 
Last edited:

Similar threads

Replies
15
Views
3K
Replies
34
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
1
Views
2K