(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

y = 2^(sin x)

Find derivative.

2. Relevant equations

3. The attempt at a solution

[itex]y = 2^{sin x}[/itex]

[itex]ln y = ln (2^{sin x})[/itex]

[itex]ln y = sin x ln(2)[/itex]

[itex]y' = [ln(2)] (cos x) (2^{sin x})[/itex]

Yet, according to some rule in the book:

a^x derivative is ln a times a^x, or in this case ln(2)2^(sin x)

But usually these rules don't conflict with other valid ways of coming to the answer. Wolfram shows me my answer, mathway shows me the book's answer.

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# Homework Help: Some more logarithm stuff giving me trouble

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