# Some pre algebra help

1. May 24, 2006

### eeeeee

could some one help me fine the products with these problems.

-3x3(2x3 +3x-4)

2. May 24, 2006

### eeeeee

the little 3s mean to the third power

3. May 24, 2006

### pendulum

x1=x2=x3=0
x4=0.879615
x5= -0.439807 + i 1.44232
x6= -0.439807 - i 1.44232

I found arithmetically. I hope I'm right

4. May 24, 2006

### eeeeee

I am pretty sure that is not the right answer

5. May 24, 2006

### eeeeee

here are 2 others
1. (x+1)(x-2)

2.(4x-2)(-x+3)

6. May 24, 2006

### pendulum

I've just checked my answers and they are absolutely right.
Unless you are not asking for the solution of the
-3(x^3) ( 2(x^3) + 3x - 4) = 0
What you've written (about the 2 others) has nothing to do.

7. May 24, 2006

### eeeeee

i need to find the product of

1. (x+1)(x-2)

2.(4x-2)(-x+3)

8. May 24, 2006

### eeeeee

nvm i figured it out

9. May 24, 2006

### pendulum

(x+1)(x-2) = (x^2) -x -2 = 0 -> x1= 2
and x2= -1

(4x-2)(-x+3) = -4(x^2) +14x -6 =0 -> x1 = 3
and x2 = 0.5

But again, it has nothing to do with the first one.

10. May 24, 2006

### d_leet

Stop assuming what is being posted are equations because they are not. Do you see an equal sign in any of the above posts exclusing your own? The OP has posted expressions asking for help in expanding them, there is nothing to solve for since there is no equation at all.

11. May 24, 2006

### vsage

(Homework help should be posted in the homework help forums)

12. May 25, 2006

### pendulum

Ok I'm sorry. Stop shooting! The problem is with my english.

13. May 25, 2006

### HallsofIvy

"=" has nothing to do with "English"!

14. May 28, 2006

### pendulum

I thought products meant roots.

15. May 28, 2006

### pendulum

Again, you're right. I 'm sorry.

16. May 28, 2006

### Crusty

^ means to the power of.
Is this right?

-3x^3(2x^3 +3x-4) = -6x^6 - 9x^4 + 12x^3

(x+1)(x-2) = x^2 + x - 2x -2 = x^2 - x - 2

(4x-2)(-x+3) = -4x^2 + 2x + 12x - 6 = -4x^2 + 14x - 6