Sound waves - Destructive Interference

AI Thread Summary
Two identical loudspeakers, 2 meters apart, create sound waves that can interfere destructively. The problem involves finding the frequency below which no position along a perpendicular line from one speaker experiences destructive interference. The path difference for destructive interference is expressed as a function of the detector's distance from the speaker. The lowest frequency corresponds to the highest wavelength, leading to the conclusion that the maximum wavelength occurs at the boundary when the detector is at the initial position. The discussion highlights the importance of analyzing the derivative to identify the maximum value of the wavelength function.
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Homework Statement


Two identical loudspeakers are located at points A & B, 2m apart. The loudspeakers are driven by the same amplifier (coherent and are in the same phase). A small detector is moved out from point B along a line perpendicular to the line connecting A & B. Taking speed of sound in air as 332 m/s, find the frequency below which there will be no position along the line BC at which destructive interference occurs.

Homework Equations


The Attempt at a Solution


I am not sure how would I approach this problem. I started with calculating the path difference when the detector is at a distance x from its initial position,
\Delta x=\sqrt{4+x^2}-x
For destructive interference,
\sqrt{4+x^2}-x=\left(n+\frac{1}{2} \right)\lambda
where ##\lambda## is the wavelength of the wave.

I don't know how should I proceed from here.

Any help is appreciated. Thanks!
 

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Think:
What does lowest frequency mean for the wavelength?
How does the pathlength - difference change if the detector moves along x?

ehild
 
ehild said:
Think:
What does lowest frequency mean for the wavelength?
How does the pathlength - difference change if the detector moves along x?

ehild

Lowest frequency means highest wavelength. For that should I substitute n=0? And then I will get ##\lambda## as a function of x. So should I find maximum of this function?
 
Yes, do it...

ehild
 
ehild said:
Yes, do it...

ehild

I tried that but had no luck. Substituting n=0,
\lambda=2(\sqrt{4+x^2}-x)
Differentiating w..r.t x
\frac{d\lambda}{dx}=2(\frac{x}{\sqrt{4+x^2}}-1)=0
This equation has no solution for x. :(

EDIT: Looks like the function has its maximum value at x=0. And this gives me the right answer. Thanks ehild! :smile:
 
There is no local maximum, but the function decreases with x, and x≥0. The function takes the maximum at the boundary.

ehild
 
ehild said:
There is no local maximum, but the function decreases with x, and x≥0. The function takes the maximum at the boundary.

ehild

Yes I realized it when I examined the derivative. :)
 
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