Source Transformations: Find Vth & Rth

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The discussion focuses on finding the Thevenin equivalent circuit through source transformations, specifically determining Vth and Rth. The calculated values are Vth=60V and Rth=30Ω, with one participant expressing uncertainty about the legality of their steps. It is pointed out that a mistake was made in the transformation of a voltage source into a current source, as the associated resistor must be in parallel with the current source. Additionally, the importance of working systematically from one end of the circuit to the other is emphasized, suggesting that converting back and forth between source types can simplify the process. The conversation concludes with a commitment to rework the solution based on this feedback.
jdawg
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Homework Statement


Find the thevenin equivalent circuit by performing source transformations only.

Homework Equations

The Attempt at a Solution


Answers: Vth=60v and Rth=30.
I managed to get Rth correct, but I'm not sure if everything I did was "legal". I can't seem to find Vth.
 

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jdawg said:

Homework Statement


Find the thevenin equivalent circuit by performing source transformations only.

Homework Equations

The Attempt at a Solution


Answers: Vth=60v and Rth=30.
I managed to get Rth correct, but I'm not sure if everything I did was "legal". I can't seem to find Vth.
In the 3rd circuit, your transformation of V into I is wrong since the resistor and current source(transformed) are not in parallel. But you don't need a 3rd step. I think in the 2nd circuit itself, the answer is obvious (60V).
 
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Your third step is incorrect. When a voltage source is transformed into a current source the associated resistor must end up in parallel with the current source. Also, you should work from one end of the circuit to the other, towards the output, in stages.

Your first step, converting the 4 A source to a 40 V source allowed you to "swallow up" one 10 Ω resistor. The logical next step would be to convert this "new" voltage source and resistance back to a current source allowing you to "swallow up" more of the circuit with simple parallel or series combinations. Don't be afraid to convert back and forth between source types if it allows you to make progress in reducing the circuit.
Fig1.png
 
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Thanks, I'll try reworking it!
 

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