Space Shutte Centripetal force problem

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SUMMARY

The discussion focuses on calculating the velocity required for a space shuttle to release a satellite into a circular orbit 555 km above the Earth. The formula used is V = √(GM/r), where G is the gravitational constant (6.67 x 10^-11) and r is the total distance from the center of the Earth, which includes the Earth's radius (approximately 6000 km). Participants emphasize the importance of incorporating the Earth's radius into the calculation to determine the correct orbital speed.

PREREQUISITES
  • Understanding of gravitational constant (G)
  • Familiarity with circular motion and centripetal force concepts
  • Knowledge of Earth's radius (approximately 6000 km)
  • Ability to manipulate and solve equations involving square roots
NEXT STEPS
  • Calculate the gravitational parameter GM using Earth's mass and radius
  • Learn about orbital mechanics and the principles of satellite motion
  • Explore the relationship between centripetal force and gravitational force
  • Study the effects of altitude on orbital velocity
USEFUL FOR

Students studying physics, aerospace engineers, and anyone interested in orbital mechanics and satellite deployment calculations.

mayla1190
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Homework Statement



The space shuttle releases a satellite into a circular orbit 555km above the earth
how fast must the shuttle be moving when release occurs in m/s?

Homework Equations



V= square root ((GM)/r)
r= 555000
G= 6.67 * 10^-11
-mass was not given so I am not sure how to plug it in
-I got that equation but making force of gravity proportional to centripetal force
 
Last edited:
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How about you show what you did? That will help to see where you went wrong.
 
Welcome to PF, mayla1190! :smile:

You do need some extra information to solve this problem.
I think you need the radius of the earth, but you can look this up (6000 km).
From this you can also calculate GM (using g).

Btw, your r is not quite right, since you've neglected to include the radius of the earth.
 

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