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Special relativity effects in general relativity

  1. Jul 1, 2014 #1
    SR is a theory based on flat space-time, and all of its effects are there in a flat space-time framework.My question is, how is SR compatible with GR, since GR uses curved space-time?

    Or to say it better how are time dilation, length contraction and relative simultaneity manifested in curved space-time, I hope somebody could give me a comparision.

    Thanks in advance.
     
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  3. Jul 1, 2014 #2

    A.T.

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    SR is an approximation for regions of space-time where the effects of curvature are negligible. In GR free falling frames locally approximate the inertial frames SR deals with.
     
  4. Jul 1, 2014 #3

    pervect

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    To draw an analogy, the difference between SR and GR is the difference between living on a plane, and on the surface of a sphere. (There's nothing special about the sphere in particular, I am using it as a specific example of the more general notion of a curved 2 dimensional geometry).

    Living on the surface of a sphere, you have to deal with the effects of curvature on the geometry, but they only become important if you make "long enough" journeys. For instance if the sphere is the surface of the Earth, and you are walking to the corner store, the effects of curvature are negligible and you can successfully navigate as if the curved surface of the Earth was a flat plane. If you are sailing across the ocean, you will encounter significant errors if you do not account for curvature.

    The boundary of how large a distance you can describe without accounting for the effects of curvature depends on how much accuracy you need.

    The notion can be made more rigorous, for instance by talking about the plane tangent to the surface of the sphere, and creating a mapping between points on the tangent plane and points on the sphere.

    Euclidean plane geometry is analogous to the Minkowskii geometry of flat space-time, the geometry of the sphere is analogous to the geometry of General Relativity. At every point in the curved geometry of General Relativity, we have a tangent space that's perfectly flat. The geometry of this flat tangent space is described by special relativity.

    To answer your specific question about time dilation, length contraction, and relative simultaneity, they all consequences of the Minkowskii geometry of space-time, and they manifest themselves in the locally flat tangent space as usual. GR adds additional effects on top of the effects due to special relativity due to the curvature of space-time which only become significant when you analyze a sufficiently large region of space-time.

    One way of describing these "extra effects" is to introduce a metric. In a flat geometry, the metric coefficients are all unity. Thus in a spatial geometry, we have an invariant distance ds that is the same for all observers, which we can write as ds^2 = dx^2 + dy^2 + dz^2. In a flat space time geometry, we haven an invariant Lorentz interval ds which we can write as ds^2 = dx^2 + dy^2 + dz^2 - dt^2.

    In a curved geoemtry, we need to introduce metric coefficients, which are in general a quadratic form. For instance on the surface of the earth, a change in lattiude of 1 degree always represents a constant distance, but a change in longitude of 1 degree does not, the distance corresponding to a longitude change of 1 degree varies with lattitude. This behavior can be mathematically described by a quadratic form involving lattitude and longitude. Without metric coefficients, there is no way to account for the fact that the distance represented by a degree of longiutde varies with lattitude.
     
  5. Jul 1, 2014 #4
    @Pervect, thanks for the great answer.

    I was wondering how exactly the SR effects that I mentioned correspond to curved space time. Will a curve in space get length contracted relative to a moving frame, or not, how do effects from flat space-time transmit to curved space-time?
     
  6. Jul 1, 2014 #5

    WannabeNewton

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    You can in GR do everything that you do in SR so long as the calculations are done at a single event. This means in particular that length contraction of a (Born-rigid) rod relative to some observer is only defined at the event at which the rod passes right by the observer. The same goes for SR time dilation, just replace "rod" with "ideal clock". The length contraction and time dilation so obtained will contain not only the usual SR kinematic effects but also the GR effects of gravity. In order to extend these concepts globally, to all of space-time, you need a field of observers whose world-lines fill all of space-time. Actually this is not even special to GR. The same goes for SR when dealing with fields of arbitrarily accelerating, non-intersecting observers.

    I can provide some examples if you wish.
     
  7. Jul 1, 2014 #6
    It would be great if you could give me some examples, cause this is very fuzzy for me, I haven't had almost any experience with GR. In curved space time the shortest path between two points is a curve, in flat space-time it is a line. But can that curve contract in some way, like a line can in SR?
     
  8. Jul 1, 2014 #7
    I have many questions regarding this topic, so I'll ask some and I hope I will get some answers.
    The first one is connected to the motion in GR. For instance, if somebody would travel from the Earth to Sun, he would do in a curved path, right? How is this different from the classical 'distance' in both Newtonian physics and in SR. Is the time dilation that he will undergo under that curved path simply a product of its velocity (and acceleration because of the curve) during the path or is he also affected by gravitational time dilation. I had an idea that maybe gravitational acceleration is what causes the curve of his path to the Sun, and I don't know is this correct, so maybe someone will correct me.

    And when mentioning rods like you did before, WBN, if we compare SR and GR, it seems that a rod that is straight in SR becomes curved in GR, because the space itself is curved. Is this true, and is there a way to construct a rod, or any object that basically isn't curved in curved space-time.
     
  9. Jul 1, 2014 #8

    ChrisVer

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    I don't understand what you are trying to ask in your last post....
    The path won't be curved- the paths are always straight lines.... the straight lines change according to your spacetime geometry.... (am I wrong?)

    I don't think that in general an extended object in GR is curved... I'd preferably say that it's subject to tidal forces and thus can be stressed, it can be curved but in fact it takes the form at which it can have the least action satisfied ...
     
  10. Jul 2, 2014 #9

    How will the path not be curved since spacetime itself is curved?
     
  11. Jul 2, 2014 #10

    HallsofIvy

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    I suspect Chris Ver should have said "geodesics", rather than "straight lines". Geodesics, locally, look like straight lines.
     
  12. Jul 2, 2014 #11
    But travelling with geodesics still makes you accelerate, right, and therefore experience different time dilation at each point of the curve?
     
  13. Jul 2, 2014 #12

    A.T.

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    Travelling on geodesics worldliness means zero proper acceleration.
    http://en.wikipedia.org/wiki/Proper_acceleration
    Of course you can still have coordinate acceleration (dv/dt) in some reference frame..

    Kinetic time dilation depends on speed, while gravitational time dilation depends on position.
     
  14. Jul 2, 2014 #13

    WannabeNewton

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    In that case I'm afraid my examples won't make any sense to you. I was going to give you examples from Schwarzschild space-time on calculating length contraction of rods, time dilation of clocks, and kinematic redshift of photons when Lorentz transforming from radially infalling observers to observers in circular free fall orbit but they all make use of the Lorentz frame formalism and if you haven't had any experience with GR it won't be of much use.

    There is no gravitational time dilation in a freely falling frame. I can show you this explicitly if you wish but the comment from above will still hold.

    My comment from the other thread still applies here. If you are truly determined to learn SR and GR then you need to start working through a textbook. It's how everybody else here learned it and it's the only way you can learn it. If you are under the impression that geodesics correspond to acceleration then it's clear that you need to start at the basics of GR before asking questions that are mired with much more subtelty such as whether spatial curves on space-like foliations have a notion of length contraction.
     
  15. Jul 2, 2014 #14

    PeterDonis

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    Because path curvature and spacetime curvature are two different things, and they need to be carefully distinguished in order to properly understand GR.

    Path curvature, physically, corresponds to proper acceleration, i.e., acceleration that you actually feel, i.e., feeling weight. So a freely falling object, which is weightless, feeling zero acceleration, is traveling on a path that is not curved--it is straight. These paths are called "geodesics" in order to make clear that it is only the straightness of the path, by the definition I just gave, that is being asserted. Saying that a given path is a geodesic says nothing about the curvature of the spacetime in which it is embedded, and vice versa--you can have straight paths (geodesics) in curved spacetime, and you can have curved paths (accelerated worldlines) in flat spacetime.

    Spacetime curvature, physically, corresponds to tidal gravity. The way you test for tidal gravity is to compare nearby straight paths (geodesics) that start out parallel, where "parallel" here means "at rest relative to each other" if we are talking about the worldlines of freely falling objects. If nearby geodesics that start out parallel don't stay parallel, spacetime is curved; physically, if two nearby freely falling objects that start out at rest relative to each other don't stay at rest relative to each other, tidal gravity is present.

    Bear in mind, again, that these definitions may not match up with your intuitions; but that's a problem with your intuitions, not with the definitions. These definitions are adopted in GR because they work: they give us a theory of spacetime and gravity that has passed very stringent experimental tests.
     
  16. Jul 2, 2014 #15
    Ok, thanks for the answers, even though I feel I need time and knowledge to really get to know them.

    So for instance, if a rocket is travelling from Earth to the Sun, will it travel by geodesic or not? Since the only things that travel by geodesic, if I understand correctly, are free-falling objects?
     
  17. Jul 2, 2014 #16

    PeterDonis

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    If it's firing its engines, so the rocket passengers feel weight, then no, it's not traveling on a geodesic. If it's not firing its engines, so the rocket passengers are weightless (which is how spacecraft we can make with today's technology travel most of the time), then it's traveling on a geodesic.
     
  18. Jul 2, 2014 #17
    I understand the basics, free fall acelleration and curved space-time upward acceleration cancel each other out so the free falling object is inertial. So basically speaking, the rocket will still travel on a curve, but it won't be a 'straight curve' or to say it better, a geodesic? If the rocket isn't free falling, then the only acceleration in this case that it gets is from curved spacetime (the upward one). So it will undergo kinematical time dilation because of velocity and gravitational time dilation because of the space time curvature and its acceleration that arises from this fact?

    This is extremely hard to conceptualize, if I may add, but thanks for your effor, I guess everybody here had a similar problem in their first steps.
     
  19. Jul 2, 2014 #18

    A.T.

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    If its accelerometer measures zero proper acceleration, then the wordline (path in space-time) is a geodesic.

    In other words, when no forces (other than gravity which doesn't count as a force in GR) are acting on the rocket (or if they all cancel), then its wordline (path in space-time) is a geodesic.

    Yes. With engines off in space you are usually free falling.
     
  20. Jul 2, 2014 #19
    You still may do so, I think it will help me. Especially the comparision between SR effects in flat space time vs curved space time
     
  21. Jul 2, 2014 #20

    PeterDonis

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    That is not "the basics", it is incorrect. There is no such thing as "curved spacetime upward acceleration".

    Do you mean a rocket with its engines firing, or not firing? That is the key physical difference between the two cases, so it gets frustrating when people keep describing scenarios without even specifying this key variable.

    If the rocket's engines are firing, so its passengers feel weight, it is traveling on a curved path.

    If the rocket's engines are not firing, so its passengers are weightless, it is traveling on a straight path.

    That is all you need to know to determine whether or not the rocket's path is curved. You don't need to know *anything* about the spacetime curvature.

    No.

    No.
     
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