Specific heat capacity & heat capacity

  • Thread starter ellieee
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  • #1
ellieee
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Homework Statement:
what is the numerical value of the ratio ?
Relevant Equations:
Q=mcθ
Q=mc
the answer is 1/2 , but when I did the working out, I got 2/1.. so I'm quite confused
 

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Answers and Replies

  • #2
Orodruin
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The ratio has physical dimension. You therefore cannot assign a dimensionless numerical value.
 
  • #3
ellieee
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The ratio has physical dimension. You therefore cannot assign a dimensionless numerical value.
then are you able to explain the answer key ?
 
  • #4
Orodruin
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then are you able to explain the answer key ?
The question is ill posed.
 
  • #5
Orodruin
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But with regards to how the question (being ill posed) wants you to do things ...

You have taken heat capacity / specific heat capacity instead of specific heat capacity / heat capacity.
 
  • #6
ellieee
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But with regards to how the question (being ill posed) wants you to do things ...

You have taken heat capacity / specific heat capacity instead of specific heat capacity / heat capacity.
how ..? isn't specific heat capacity = mcθ and heat capacity = cθ?
 
  • #7
Steve4Physics
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isn't specific heat capacity = mcθ and heat capacity = cθ?
No.

Specific capacity is ‘c’ (lower case ‘c’).
Heat capacity is ‘C’ (upper case ‘C’)
C = mc
Warning: it's easy to mix up 'c' and 'C'!

That means you are simply being asked to find ##\frac c {mc}##.

Other notes...

The question contains distractors - unnecessary information to test your ability to identify the relevant information.

Q=mcΔθ gives the heat transferred when an object of mass m and specific heat capacity c changes temperature by Δθ. It is not required in this question.

Q = CΔθ gives the heat transferred when an object of heat capacity C changes temperature by Δθ. It is not required in this question.

The correct answer should have units (as already noted by @Orodruin in Post #2).

Edit - typo' corrected.
 

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