(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The temperature of a brass cylinder of mass 100g was raised to 100 degree celsius and then transferred to a thin aluminium can of negligible heat capacity. The aluminium can contained 150g of paraffin at 11 degree celcius. If the final steady temperature after stirring was 20 degree celsius, claculate the specific heat capacity of paraffin

(Neglect heat losses, and assume specific heat capacity of brass= 38 J/gK

2. Relevant equations

Specific heat capacity * mass * change in temperature = Energy lost/gained

3. The attempt at a solution

The answer given by my teacher is: 2250J/Kg.K

My answer and workings:

100 * 28 * 80 = 150 * 9 * Specific heat capacity of paraffin

Specific Heat Capacity = 225 J/g.K

Even if I change this value to J/kg.K (which I don't know how to), I won't get the answer my teacher gave- that much I can tell :-(

Someone I asked gave the correct answer, but they didn't take the weight of the cylinder into account. Why is this possible?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Specific Heat Capacity of a brass cylinder

**Physics Forums | Science Articles, Homework Help, Discussion**