Speed and distance in a car crash

AI Thread Summary
To establish the speed and distance involved in a car crash, key calculations include using the conservation of momentum and friction coefficients. The discussion highlights that the weight of both vehicles and the initial speed of the cars are crucial for determining lateral movement after impact. It suggests that a speed of around 25 MPH could result in approximately 27 cm of lateral movement, but emphasizes that this is based on several assumptions. The importance of expert testimony is noted, as judges may not be swayed by calculations alone without credible evidence. Ultimately, proving fault in the accident hinges on demonstrating whether the other driver acted unsafely during the maneuver.
elijahfischer
Messages
2
Reaction score
0
I had a car accident and need to go to court to prove my case. Please help me figure this out with what formulas I need to use. Also please explain details so I can explain it to the judge. Thanks. Here it is: I was traveling when I hit a car that pulled out in front of me. She claims she was making a left turn and that I hit her vehicle on the corner hard enough to push her vehicle sideways. I need to know how fast I would need to be going to move the back of her vehicle sideways anything more than an 1".
Here is the data:
Weight of my vehicle: 3196 lbs
Weight of her vehicle: 3009 lbs
My speed before impact: 25 MPH
Her speed before impact: o mph
Payment: Asphalt
Weather conditions: Dry 70 degree F
 
Physics news on Phys.org
Jones and Childers report coefficients of friction of about µ=0.7 for dry roads

The force opposing motion would be µW=(M+W)a: W is the weight of her car and M is the weight of yours - a is the deceleration. the distance slid is given by d=v²/2a where v is the initial speed of both cars.

Back of envelope, you'd use conservation of momentum to estimate the speed of both vehicles together after the collision but before lateral movement.

Mu=(M+W)v where u is the speed of your car before the impact.

Plugging in the numbers I get 27cm lateral movement: about a foot.
There's an awful lot of assumptions in that but at least it does not look all that sensitive to even quite large changes in speed (I still get less than a foot for u=50mph).
That's for pushing the whole car - for just the back you'd be rotating about the front wheels and only the weight on the back wheels will count for F. If I guess half (it will be less - engine is in the front right?) and just stay linear the guess turns into 72cm - a bit over two feet.

However: my experience is that judges are seldom impressed by this sort of reasoning unless you get an expert witness to deliver it. What you really need is an expert in accidents or a practical experiment.
 
If she attempted a left turn from opposing traffic or from a side street while it was not safe to do so would mean that her manoeuvre was the probable cause of the accident.
If you rear-ended her then most likely your inattention on the road that is the probable cause of the accident. Unless she changed lanes and braked in front of you and you hit her in which case the main party at fault is for a debate.
Unless you can prove to the judge that you are an expert in some aspect of road collisions and damage ensued, I doubt that a momentum and energy calculation would impress the judge, as SB stated.
 
Thanks for the help. Will keep that in mind about want impresses the judges.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top