Speed,mass,energy and a question.

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SUMMARY

The discussion centers on the relationship between mass and energy at high velocities, specifically at 2 x 10^8 m/s. It clarifies that the equation E=mc² does not imply that mass transforms into energy at the speed of light; rather, it serves as a conversion factor for energy equivalent to mass at rest. For moving mass, the correct equation is E = mc² / √(1 - v²/c²), which indicates that while mass remains constant, kinetic energy increases significantly as velocity approaches the speed of light.

PREREQUISITES
  • Understanding of Einstein's mass-energy equivalence principle (E=mc²)
  • Familiarity with relativistic physics concepts
  • Knowledge of kinetic energy calculations in physics
  • Basic grasp of the speed of light (c) and its implications
NEXT STEPS
  • Explore the implications of relativistic mass and energy in high-speed physics
  • Study the derivation and applications of the equation E = mc²
  • Learn about the Lorentz factor and its role in relativistic equations
  • Investigate the concept of kinetic energy at relativistic speeds
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Students of physics, educators in relativity, and anyone interested in the principles of mass-energy equivalence and high-velocity motion.

shihab-kol
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Suppose instead of moving at the speed of light , someone moves at a speed of 2*10^8 m/s .Then will his mas and energy exist simultaneously ? I mean mostly energy and some mass ?
 
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At that velocity the person's mass will remain unchanged but their kinetic energy will be immense.
 
shihab-kol said:
Suppose instead of moving at the speed of light , someone moves at a speed of 2*10^8 m/s .Then will his mas and energy exist simultaneously ? I mean mostly energy and some mass ?
The way your question is phrased leads me to wonder if you are laboring under a misconception; one I have come across before.

Are you under the impression that the equation E=mc2 means that a mass moving at the speed of light has "turned into" energy. If so, that is not the meaning of this equation. While the equation contains a speed "c", this does not imply any movement on the part of the mass. The c2 part of the equation just acts as a conversion factor. The equation gives the energy equivalent of M, or the energy you would get if the mass were converted to energy (such as in the combination of two antiparticles with a combined mass of m).

In fact, this particular equation only works when you assume that mass m is at rest with respect to you. If it is in motion at velocity v, then you use
[tex]E = \frac{mc^2}{\sqrt{1-\frac{v^2}{c^2}}}[/tex]

Which, if you subtract mc^2 from it, will give you the kinetic energy of of mass m at velocity v.

As Drakkith has already pointed out, the mass of m will not change as v increases. However E will approach infinity as v approaches c.
 
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