Speed of a Sneeze: Solve Homework Statement

  • Thread starter Thread starter Goatsenator
  • Start date Start date
  • Tags Tags
    Speed
AI Thread Summary
The discussion revolves around calculating the airspeed during a cough based on a given volume flow rate of 5.3 x 10-3 m3/s and varying trachea diameters. The initial approach involved using the formula for volume flow rate, but the user received incorrect feedback on their calculations. Suggestions were made to consider working backwards to find the solution. The key focus is on determining the airspeed as a multiple of the speed of sound, specifically for trachea diameters of 19 mm and 7.8 mm. The conversation emphasizes the importance of accurate calculations in fluid dynamics.
Goatsenator
Messages
18
Reaction score
0

Homework Statement



When you cough, you expel air at high speed through the trachea and upper bronchi so that the air will remove excess mucus lining the pathway. You produce the high speed by this procedure: You breathe in a large amount of air, trap it by closing the glottis (the narrow opening in the larynx), increase the air pressure by contracting the lungs, partially collapse the trachea and upper bronchi to narrow the pathway, and then expel the air through the pathway by suddenly reopening the glottis. Assume that during the expulsion the volume flow rate is 5.3 x 10-3 m3/s. What multiple of the speed of sound xs (= 343 m/s) is the airspeed through the trachea if the trachea diameter (a) remains its normal value of 19 mm and (b) contracts to 7.8 mm?




2. Homework Equations / Solution Attempt

I applied the definition of volume flow rate = (area)(velocity) then divided that answer by 343 m/s to get the ratio but it says that it's wrong.
 
Physics news on Phys.org
Goatsenator said:
I applied the definition of volume flow rate = (area)(velocity) then divided that answer by 343 m/s to get the ratio but it says that it's wrong.

What was the answer?

Have you tried working backwards? it might help ; )
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top