Speed of a sound wave (compressibe flow)

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SUMMARY

The speed of a sound wave in compressible flow is defined as 'c', with the flow velocity represented as 'U'. When a sound wave travels in the same direction as the flow, its resultant velocity is 'c + U', and in the opposite direction, it is 'c - U'. At Mach 1, the sound wave's speed is zero relative to the sound source, as both travel at the same velocity, causing the waves to stack and form a shockwave. Understanding these principles is crucial for analyzing sound propagation in moving media.

PREREQUISITES
  • Understanding of compressible flow dynamics
  • Familiarity with the concept of Mach number
  • Knowledge of wave propagation in fluids
  • Basic principles of relative motion
NEXT STEPS
  • Study the principles of compressible flow in fluid dynamics
  • Learn about the formation and characteristics of shockwaves
  • Explore the relationship between sound speed and Mach number
  • Investigate the effects of moving media on wave propagation
USEFUL FOR

Students and professionals in aerospace engineering, fluid dynamics researchers, and anyone interested in the physics of sound in moving environments.

xJJx
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Hi, there is no particular question that I need help on, just something my lecturer told us in lesson which I couldn't quite understand so i'd like to check my understanding on this. I know that the speed of a soundwave is 'c' in undisturbed flow. Suppose the flow velocity is 'U'. If the soundwave is convected by the flow, would the resultant velocity of the soundwave be 'c + U' if the wave is traveling in the same direction as flow, and would it be 'c - U' (vector sum) if the wave is traveling in the opposite direction to the flow? Does the centre of the sound wave travel at a speed of U whilst the ripples propagate at speed c?
Also, my teacher said that at Mach 1, the speed of the sound wave is exactly 0, which is why the soundwaves stop and compile to form a shockwave. I don't understand how the speed can be 0 when U=c at mach 1.
thank you!
 
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The "Sonic boom" is experienced by an outside observer. The source of the sound (a jet plane, for example) is moving at Mach 1. The medium (air) through which the sound travels is not moving at Mach 1
 
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xJJx said:
would the resultant velocity of the soundwave be 'c + U' if the wave is traveling in the same direction as flow, and would it be 'c - U' (vector sum) if the wave is traveling in the opposite direction to the flow?
Yes.
xJJx said:
Does the centre of the sound wave travel at a speed of U whilst the ripples propagate at speed c?
Yes.
xJJx said:
Also, my teacher said that at Mach 1, the speed of the sound wave is exactly 0, which is why the soundwaves stop and compile to form a shockwave. I don't understand how the speed can be 0 when U=c at mach 1.
The speed is not zero. It is zero relative to the sound source since they travel at the same velocity (only considering the moving direction of the sound source). So, as soon as the sounds source emits a sound wave, it "follows" it since they travel at the same velocity. When the sound source emits another sound wave, it therefore "stacks" on the previous sound wave.

speed%2Bof%2Bsound.jpg
 

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The bottom line is you just have to remember that sound travels at the speed of sound ##c## (sometimes written as ##a## as well) relative to the air, so if the air is moving, you have to take that into account if you are looking at the wave speed relative to a stationary observer.
 
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jack action said:
Yes.

Yes.

The speed is not zero. It is zero relative to the sound source since they travel at the same velocity (only considering the moving direction of the sound source). So, as soon as the sounds source emits a sound wave, it "follows" it since they travel at the same velocity. When the sound source emits another sound wave, it therefore "stacks" on the previous sound wave.

Thank you so much! this was very helpful. It creeps up a lot in exam questions so it's worth knowing
 
boneh3ad said:
The bottom line is you just have to remember that sound travels at the speed of sound ##c## (sometimes written as ##a## as well) relative to the air, so if the air is moving, you have to take that into account if you are looking at the wave speed relative to a stationary observer.
thank you!
 

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