Speed of Moon without Sun gravity.

[SpeedofLight]

What he said.

Hello D H,
you didn't understand me, as i said:

the moon makes 360 degrees around Earth with respect to stars the Earth-moon system moves 26.92952225 degrees around the sun.We can calculate ø from the period of one heliocentric revolution of the Earth-moon system (365.2421987 days):
ø = (360 degrees / 365.2421987 synodic days) x 27.32166088 synodic days = 26.92952225 degrees. So,the speed of moon without Sun gravity should be like this:
V = (2 * pi * R / T)*cos[26.92952225]
Is this CORRECT?

then you said:

No.

Assuming no other bodies are present, Newton's law of gravity yields an equation for the period of a pair of bodies orbiting their common center of mass. You need to use that equation.

I will tell you a simple example:
The velocity vector is defined by the speed and also by the direction of motion. Objects experiencing no net force do not accelerate and, hence, move in a straight line with constant speed: they have a constant velocity. However, even an object moving in a circle at constant speed has a changing direction of motion. The rate of change of the object's velocity vector in this case is the centripetal acceleration.

The centripetal acceleration varies with the radius of the path and speed of the object, becoming larger for greater speed (at constant radius) and smaller radius (at constant speed). If an object is traveling in a circle with a varying speed, its acceleration can be divided into two components, a radial acceleration (the centripetal acceleration that changes the direction of the velocity) and a tangential acceleration that changes the magnitude of the velocity.
So, this formula V = (2 * pi * R / T)*cos[26.92952225] is right,that should find speed of moon without sun gravity from Earth-Moon System(i think the orbit of moon would be very close to circle).
The Speed of Moon Relative to Earth without the gravitational pull of the sun from Earth-Moon System is 3282.9 km/h (roughly).

Thank you.