Speed of proton as fraction of c

In summary, to find the speed and momentum of a proton with a kinetic energy of 1000MeV, you will need to use the equations KE= (1/2)mv2, KE= \gammamc2, p=mv, and \gamma=1/(sqrt(1-(v2/c2))). However, it is important to note that the formula given for kinetic energy in the conversation is incorrect. The correct formula is K=E-E_0=(\gamma-1)mc^2, where E is the total energy, E_0 is the rest energy, and \gamma is the Lorentz factor.
  • #1
sheepcountme
80
1

Homework Statement



Find the speed (as a decimal fraction of c) and momentum of a proton that has a kinetic energy of 1000MeV. The proton mass is 1.673x10-27kg, or 938 MeV/c2.

Homework Equations



KE= (1/2)mv2
KE= [tex]\gamma[/tex]mc2
p=mv
[tex]\gamma[/tex]=1/(sqrt(1-(v2/c2)))

The Attempt at a Solution



I'm not too sure about the KE, it's supposed to be 0.875c but I can't get that value...
I've been solving for gamma and then solving for u, but I get outrageous values.
 
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  • #2
Your formula for the kinetic energy is wrong. That's probably why you're getting non-sensical results.
 
  • #3
Really? It's what our book gives us :/ Mind telling me what I should be using?
 
  • #4
I doubt that's what your book says. It's more likely you're just confusing the total energy with the kinetic energy. The total energy of an object of rest mass m is given by [itex]E=\gamma mc^2[/itex]. Note when the object isn't moving and therefore has no kinetic energy, you still have [itex]\gamma=1[/itex] and [itex]E_0=mc^2[/itex]. This energy E0 is called the rest energy; it's the energy an object has just because it has mass. The kinetic energy of an object is the amount of energy in excess of the rest energy. Since the total energy is equal to [itex]E=\gamma mc^2[/itex] and the rest energy is [itex]E_0=mc^2[/itex], the kinetic energy is equal to [itex]K=E-E_0=(\gamma-1)mc^2[/itex].
 
  • #5


I would like to clarify some of the equations and values in this problem. The first equation, KE= (1/2)mv2, should be KE= (1/2)mv^2. Additionally, the value of 1000 MeV given for the kinetic energy of the proton should be converted to Joules (J) using the conversion factor 1 MeV = 1.602 x 10^-13 J. This gives a kinetic energy of 1.602 x 10^-10 J.

Next, we can use the equation KE= \gammamc2 to solve for the speed of the proton. Rearranging the equation, we get:

v = c * sqrt(1 - (m0c^2/KE)^2)

Substituting the values given in the problem, we get:

v = (3.00 x 10^8 m/s) * sqrt(1 - (938 MeV/c^2 / 1.602 x 10^-10 J)^2)

Solving this equation, we get a speed of 0.999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
 

1. What is the speed of a proton as a fraction of the speed of light (c)?

The speed of a proton is approximately 0.9999999999999999999999958 times the speed of light (c). This means that it travels at 99.99999999999999999999958% of the speed of light.

2. How is the speed of a proton calculated as a fraction of c?

The speed of a proton is calculated by dividing its velocity by the speed of light (c). This ratio is often expressed as a decimal or a percentage.

3. Why is it important to express the speed of a proton as a fraction of c?

Expressing the speed of a proton as a fraction of c allows us to compare it to the speed of light, which is the fastest possible speed in the universe. This gives us a better understanding of the incredibly high speeds at which protons can travel.

4. How does the speed of a proton as a fraction of c compare to other particles?

The speed of a proton as a fraction of c is very close to the speed of other particles, such as neutrons and electrons. However, some particles, such as neutrinos, can travel at speeds that are even closer to the speed of light.

5. Can the speed of a proton ever reach the speed of light?

No, the speed of a proton can never reach the speed of light. As an object approaches the speed of light, its mass increases infinitely and it would require an infinite amount of energy to accelerate it further. Therefore, the speed of light is considered to be the upper limit of speed in the universe.

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