Speed, Velocity, Displacement & Acceleration: An Honors Physics Guide

Click For Summary
SUMMARY

This discussion clarifies key concepts in physics, specifically the differences between average speed, instantaneous speed, velocity, acceleration, displacement vectors, and resultant vectors. Average speed is calculated as total distance divided by total time, while instantaneous speed is derived using calculus as the derivative of distance with respect to time. Velocity is defined as a vector quantity representing the rate of change of displacement, and acceleration is the change in velocity over time. Displacement vectors indicate the difference in position, while resultant vectors are used to determine net effects when multiple vectors are involved.

PREREQUISITES
  • Understanding of basic physics concepts such as speed, velocity, and acceleration.
  • Familiarity with calculus, specifically derivatives.
  • Knowledge of vector mathematics, including vector addition and subtraction.
  • Ability to interpret data tables involving time and distance measurements.
NEXT STEPS
  • Study the concept of derivatives in calculus to better understand instantaneous speed and acceleration.
  • Learn about vector addition and how to calculate resultant vectors in physics.
  • Explore the relationship between velocity and acceleration in-depth through physics textbooks or online resources.
  • Practice solving problems involving average speed and instantaneous speed using real-world scenarios.
USEFUL FOR

Students in honors physics, educators teaching physics concepts, and anyone seeking to deepen their understanding of motion and vector analysis in physics.

bjr_jyd15
Messages
73
Reaction score
0
Hi I'm in an honors physics class. I don't really understand the difference between average speed and instantaneous speed. Say I'm given in data table with time (s) and distance (m). How can I find each of these? Is there a formula?

Also, what is the relationship of velocity with acceleration? My teacher said constant velocity means no acceleration? I'm not sure that makes sense?!

One more thing: What is the difference between displacement vectors and resultant vectors? I seem to be stuck. I know for one you just add the magnitudes but for the other it's pythagorean.

Any help would be great!
 
Physics news on Phys.org
Average velocity is the velocity between two points in time the slope of a line between those two points), instantaneous velocity is the speed at one point (this is found by calculus and the derivative usually, it's the slope at that point).
Acceleration is the change in velocity over time therefore for an unchanging velocity you get nothing divided by time so acceleration is nothing.
 
Average speed is the total distance traversed divided by the total time required to get there.

Instantaneous speed is the speed at an instant in time and can be viewed as the distance traversed divided by the traversal time as the traversal time is made arbitrarily small. It can be written as a derivative.

In particular, velocity is a vector quantity
\vec v = \frac {d \vec x}{dt}
where \vec x is the (vector) displacement.

A displacement vector is a vector describing the difference in location from one point to another. A resultant vector is a vector that results from adding or subtracting vectors. A resultant vector can also be a displacement vector.
 
Ba said:
Average velocity is the velocity between two points in time the slope of a line between those two points), instantaneous velocity is the speed at one point (this is found by calculus and the derivative usually, it's the slope at that point).
Acceleration is the change in velocity over time therefore for an unchanging velocity you get nothing divided by time so acceleration is nothing.

For consistency with your discussion of average-velocity and instantaneous-velocity, you should really say "average-Acceleration is the change in velocity over time". Instantaneous-acceleration is the acceleration at one point (found by calculus using the derivative...it's the slope at that point [on a velocity-vs-time graph])".
 
So when finding change in distance I should use displacement vectors right? If so , then when are resultant vectors ever useful?

Thanks.
 
I'm not sure how to phrase it, but resultant vectors can also be used to find out the net velocity of an object if it is being influenced by more than two different velocities.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 16 ·
Replies
16
Views
1K
Replies
12
Views
2K
Replies
11
Views
1K
Replies
1
Views
816
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
Replies
1
Views
2K
Replies
5
Views
2K
Replies
40
Views
3K