proace360 said:Homework Statement
You swing a 6.5 kg bucket of water in a vertical circle of radius 1.2 m.
(a) What speed must the bucket have if it is to complete the circle without spilling any water?
m=6.5
r=1.2
Homework Equations
maybe f=ma
f=m(v^2/r)
The Attempt at a Solution
What I did was set fc=6.5(V^2)/1.2, and since f=ma, I had a (or v/t)=V^2/1.2. I end up with the equation 1.2vt, which just brings me in circles. What can I do?
Spinning a bucket in a vertical circle is a physics experiment that involves rotating a bucket or container in a vertical circle around a fixed axis. This experiment demonstrates the concept of centripetal force, which is the force that keeps an object moving in a circular path.
The speed of the bucket increases as it moves downwards in the vertical circle and decreases as it moves upwards. This is because of changes in the direction of the centripetal force, which is always perpendicular to the velocity of the bucket.
The centripetal force acting on the bucket is affected by the mass of the bucket, the speed at which it is spun, and the radius of the circular path. Increasing any of these factors will result in a greater centripetal force.
As long as the centripetal force is greater than the weight of the bucket, it will continue to move in a circular path. However, if the speed is too low or the radius is too large, the bucket may not experience enough centripetal force and will fall out of the circular path.
When the bucket is spun without water, the centripetal force is provided by the tension in the string or rope. However, when water is added to the bucket, the centripetal force is provided by the combination of tension and the weight of the water. This results in a greater centripetal force and a faster rotation of the bucket.