Spinning a bucket in a vertical circle

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SUMMARY

The discussion focuses on determining the minimum speed required for a 6.5 kg bucket of water to complete a vertical circle with a radius of 1.2 m without spilling. The key equation used is the centripetal force formula, f = (mV^2)/r, which must be satisfied to maintain the water inside the bucket. The critical point is that the speed must be sufficient to generate enough centripetal force at the top of the circle to counteract the gravitational force acting on the water.

PREREQUISITES
  • Understanding of centripetal force and its equation f = (mV^2)/r
  • Basic knowledge of Newton's laws of motion
  • Familiarity with the concepts of mass, radius, and gravitational force
  • Ability to manipulate algebraic equations to solve for variables
NEXT STEPS
  • Calculate the minimum speed required using the formula V = sqrt(g * r) where g is the acceleration due to gravity.
  • Explore the effects of varying the radius on the required speed for maintaining the water in the bucket.
  • Investigate the role of gravitational force in circular motion dynamics.
  • Learn about real-world applications of centripetal force in engineering and physics.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of circular motion and forces acting on objects in motion.

proace360
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Homework Statement


You swing a 6.5 kg bucket of water in a vertical circle of radius 1.2 m.
(a) What speed must the bucket have if it is to complete the circle without spilling any water?

m=6.5
r=1.2


Homework Equations


maybe f=ma
f=m(v^2/r)

The Attempt at a Solution


What I did was set fc=6.5(V^2)/1.2, and since f=ma, I had a (or v/t)=V^2/1.2. I end up with the equation 1.2vt, which just brings me in circles. What can I do?
 
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proace360 said:

Homework Statement


You swing a 6.5 kg bucket of water in a vertical circle of radius 1.2 m.
(a) What speed must the bucket have if it is to complete the circle without spilling any water?

m=6.5
r=1.2


Homework Equations


maybe f=ma
f=m(v^2/r)

The Attempt at a Solution


What I did was set fc=6.5(V^2)/1.2, and since f=ma, I had a (or v/t)=V^2/1.2. I end up with the equation 1.2vt, which just brings me in circles. What can I do?

First of all think about where the greatest challenge to keep the water in the bucket will be.

What condition must be met for the water to stay in the bucket and not come out?
 
Remember that the equation f = (mV^2)/r is a condition that must be satisfied for centrifugal force; it is not a law.
 

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