- #1
Julie323
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Homework Statement
A 1.70 kg, horizontal, uniform tray is attached to a vertical ideal spring of force constant 180N/m and a 295 g metal ball is in the tray. The spring is below the tray, so it can oscillate up-and-down. The tray is then pushed down 16.5 cm below its equilibrium point (call this point A) and released from rest.
How high above point will the tray be when the metal ball leaves the tray? (Hint: This does not occur when the ball and tray reach their maximum speeds.)
Homework Equations
F=-kx
The Attempt at a Solution
I was initially thinking that the ball would leave the tray when the spring was at its uncompressed length. I solved for how far the spring was compressed at its equillibrium point. I used F=kx. (1.7+.295)(9.8)=(180)(x) This gave me a value of x of .109 m. This was wrong, any help would be greatly appreciated!