A 2.00 kg object on a horizontal frictionless surface is attached to a spring with
a spring constant 1000 N/m. The object is displaced from equilibrium 50.0 cm
horizontally and given an initial velocity of 4.0 m/s away from the equilibrium
(a) What is the frequency of motion?
(b) What is the initial potential energy of the block-spring system?
(c) What is the initial kinetic energy?
(d) What is the amplitude of oscillation?
F = -kx
F = ma
[itex]\omega[/itex] = √(k/m)
T = 1/f
f = [itex]\omega[/itex]/2[itex]\pi[/itex]
PE = 0.5kx2
KE = 0.5mv2
The Attempt at a Solution
(a) So I said:
T = 1/f → T = 2[itex]\pi[/itex]/f → T = 2[itex]\pi[/itex]√(m/k)
I subbed in my values and got T = 0.28s
Then I got f from f = 1/T and got f = 3.57s-1
(b) From PE = 0.5kx2 I got PE = 125J
(c) From KE = 0.5mv2 I got KE = 16J
(d) Its the amplitude part here that I got stuck. Could anyone clarify if my methods for the other parts were correct and point me some direction for part (d). Any help is much appreciated.