Standing Waves in Open Pipes: How Do Sound Waves Reflect at the Open End?

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SUMMARY

Standing waves in open pipes are established through the reflection of sound waves at both ends. At a closed end, a high-pressure pulse reflects as a high-pressure pulse, while at an open end, it reflects as a low-pressure pulse due to a 180º phase change. This phenomenon occurs because the high-pressure pulse disperses into the atmosphere, creating a low-pressure area that sends a pulse back down the pipe. Understanding this reflection mechanism is crucial for comprehending how standing waves are formed in acoustics.

PREREQUISITES
  • Understanding of longitudinal waves and pressure differences
  • Basic knowledge of wave behavior and reflection principles
  • Familiarity with acoustic properties of pipes
  • Knowledge of phase changes in wave mechanics
NEXT STEPS
  • Research the principles of wave reflection in different mediums
  • Explore the concept of standing waves in closed pipes
  • Learn about the acoustic properties of musical instruments, specifically flutes and clarinets
  • Investigate the mathematical modeling of wave behavior in open and closed systems
USEFUL FOR

Students of physics, acoustics researchers, and musicians interested in the sound production of wind instruments will benefit from this discussion.

nokia8650
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Hi

How are standing waves set up in open pipes - my book says that the sound waves can be reflected from the open end of the pipe - how is this possible - surely the wave would just leave the pipe?

Thanks in advance
 
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nokia8650 said:
How are standing waves set up in open pipes - my book says that the sound waves can be reflected from the open end of the pipe - how is this possible - surely the wave would just leave the pipe?

Hi nokia8650! :smile:

Sound is a traveling longitudinal pressure difference.

A sound wave in a pipe is a standing wave, and therefore cannot exist unless there is reflection at both ends.

First consider a single pulse (not a wave).

At a closed end, a pulse of high pressure is reflected as a pulse of high pressure.

At an open end, a pulse of high pressure is reflected as a pulse of low pressure (and vice versa) … a 180º "change in phase".

This is because when the high pressure pulse leaves the pipe, it spreads out spherically, rapidly becoming atmospheric pressure, and suction is created behind it.

In other words, there is a reduction in pressure behind it, and this low pressure will pulse back down the pipe.

It is this sudden reduction in pressure caused by the ability of the wave to spread out which makes the difference.

That's fairly clear for a single pulse, though not so clear for a wave, but the principle is the same.

For a lot of detail, including a rather good animation, see this Australian site: http://www.phys.unsw.edu.au/jw/flutes.v.clarinets.html#time

(Another way of looking at it is that the open end of the pipe is at high pressure, and the air beyond it is at ordinary pressure, so it behaves like a boundary between two fluids of different pressure, and so a reflection is to be expected. :smile:)
 
That makes sense, thanks a lot!
 

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