Standing waves - which instruments are closed-closed, open-open, or open-closed?

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In determining whether an instrument is closed-closed, open-open, or closed-open, it is essential to consider the ends of the instrument. Stringed instruments are closed at both ends, producing standing waves with nodes at each end and allowing for all harmonics. A flute is classified as open-open, with antinodes at both ends and a full harmonic series. Reed instruments like the clarinet are closed at one end and open at the other, resulting in a node at the closed end and only odd harmonics produced. Understanding these classifications helps clarify the behavior of different instruments in terms of standing waves and their harmonic content.
ben.tien
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Homework Statement


Okay. So I'm sort of confused about the concept of determining whether an instrument is closed-closed, open-open, or closed-open.ie. a flute, guitar, sax, oboe, clarinet. For example, is a clarinet a closed-open instrument because your mouth covers the entire mouth piece and the flute is open-open because your mouth doesn't? What are ways one can use to determine this? Thanks in advance.

Homework Equations


fn = v(n/2L) n = 1,2,3,...
fn = v(n/4L) n = 1,3,5,...


The Attempt at a Solution

 
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I take it you are happy with stringed instruments. They are clearly all "closed" at both ends. This means the standing wave pattern has a node at both ends, and the fundamental frequency has a wavelength twice the length of the string. The string is able to produce all the harmonics in the series f, 2f, 3f, etc.
With wind instruments it gets a little complicated.
A flute is open at both ends and produces a full set of harmonics. There is an antinode at both ends and the fundamental frequency has a wavelength twice the length of the tube.
Reed instruments (clarinet, oboe, bassoon, oboe etc) are closed at one end and open at the other. This means there is a node at the closed end and an antinode at the open end.
In the case of the clarinet, it is a cylindrical bore, and behaves like a standard "closed" pipe. It only produces odd harmonics (f, 3f, 5f etc) and has a fundamental frequency with a wavelength 4 times the length of the tube.
The other instruments have a conical bore. This complicates the maths a bit, but the result is that the sound that comes out contains the full set of harmonics.
There is a good treatment of this on this page and the various links from it. (It also deals with brass and other instruments)
It is very informative.
http://www.phys.unsw.edu.au/jw/woodwind.html
 
Thank you very much!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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