Starting with the definition of the Dirac delta function,

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The discussion centers on understanding the Dirac delta function, specifically how to express δ(√x) using its definition. Participants express confusion about how to manipulate the delta function when its argument is a function of x, particularly when integrating. A substitution is suggested where x is replaced with √z to facilitate the integration process, leading to an expression involving z and f(z). There is a request for clarification on the composition of distributions and functions, indicating a need for more resources on this topic. The conversation highlights the complexities of working with the Dirac delta function in non-standard forms.
skrtic
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Homework Statement



Starting with the definition of the Dirac delta function, show that \delta( \sqrt{x})um... i have looked in my book and looked online for a problem like this and i really have no clue where to start. the only time i have used the dirac delta function is in an integral with another function and never with it in this form, only like delta(x-a).looking for guidance.
 
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skrtic said:

Homework Statement



Starting with the definition of the Dirac delta function, show that \delta( \sqrt{x})

Show that \delta( \sqrt{x}) is what?
 
sorry about that.

equal to 0
 
How is the Dirac delta function defined? The problem asks you to start with this definition.
 
from what i get out of the text. it is what replaces an inner product that vanishes if x doesn't equal x'.

I also know that it's integral is unity.
 
\int_{-\infty}^{+\infty}dx\,f(x)\delta(x)=f(0)

Now, if only the argument of the delta function was \sqrt{z} instead of x ... hmmm, how could we make this happen?
 
let x= \sqrt{z} then dx=(1/2)z^(-1/2)dz

and we get \int_{-\infty}^{\infty}dz z^{-1/2} f(z^{-1/2})\delta(z^{-1/2})
 
is this a valid assumption

treat \delta(\sqrt{x}) as \delta(\sqrt{x}-0)
 
Aside: I know the hand-wavy argument is clear, but does anyone know of a source that actually defines the result of composing a distribution with a function of some sort?
 
  • #10
so assuming i made the substitution right and that was what i was supposed to do, i still don't see how i proved that it equals zero.

is that supposed to say if i plug in zero for x i get zero?

and even if i treat <br /> \delta(\sqrt{x}) <br /> as <br /> \delta(\sqrt{x}-0) <br />
i still don't have a function to plug zero into.

i am still quite confused about what i am trying to do.
 
  • #11
Hurkyl said:
Aside: I know the hand-wavy argument is clear, but does anyone know of a source that actually defines the result of composing a distribution with a function of some sort?

Section 7.4.d Composition of \delta with a function, from Mathematics for Physics and Physicists by Walter Appel.

The idea, as usual, is to to use the distribution obtained by integrating a locally integrable function against test functions to motivate a more general definition.

1. Use locally integrable g and integration to generate a distribution G.

2. Use locally integrable g \circ f and integration to generate a distribution denoted by G \circ f.

3. If x is the integration variable in 2., make the substitution y = f(x).

4. Relate G \circ f to G.

5. Use 4. to motivate the definition of T \circ f in tems of an arbitrary distribution T and differentiable and bijective function f.

If I get time tomorrow, I might type in the details.
 
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