Stat mech: partition functions for N distinguishable harmonic oscill-

Click For Summary
The discussion revolves around calculating the canonical partition function for a system of N distinguishable, non-interacting harmonic oscillators under two scenarios: one governed by Schrödinger's equation and the other by Newton's equations of motion. Participants are exploring the implications of Schrödinger's equation on the partition function, questioning whether it can be factorized into functions of position and momentum. There is confusion regarding the relationship between the partition function and the energy eigenvalues of quantum harmonic oscillators, specifically E_n = ħω(1/2 + n). The conversation highlights the need for clarity on how to approach the problem and the correct interpretation of the partition function in both contexts. Understanding these concepts is crucial for solving the homework problem effectively.
kd215
Messages
8
Reaction score
0

Homework Statement


Consider a system of N distinguishable, non-interacting harmonic oscillators. The Hamiltonian is given (shown below).
Assuming that the oscillators obey Schrodinger's equation, determine the canonical partition function for the system. Then assume the oscillators obey Newton's equations of motion and determine the partition function for the system.


Homework Equations


H = Ʃ\frac{p_i^2}{2m} +Ʃ\frac{1}{2}k|r_i-r_i^o|^2

r_i^o is the equilibrium position of the ith oscillator particle

The Attempt at a Solution



So for the first question, Schrodinger's equation means that we can only exactly know the position or the momentum for a particle, right? I've been trying to factorize the partition function as two functions that are dependent on either position or momenta. So if I do this correctly, would I obtain two functions that are both partition functions? And the one that's a function of momenta would be what I am supposed to find in the second question?

I'm just now even sure if I'm interpreting this correctly. I feel like my partition function that is a function of momenta is just the Boltzmann weighted sum.

Please just let me know if I'm even thinking in the right direction.
Thanks!
 
Physics news on Phys.org
kd215 said:
So for the first question, Schrodinger's equation means that we can only exactly know the position or the momentum for a particle, right?

I don't understand what Schrodinger's equation has to do with that.

Do you remember that the energy eigenvalues for a quantum harmonic oscillators are E_n = \hbar \omega (\frac{1}{2}+n) ?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K