Static equilibrium force decomposition problem

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Homework Help Overview

The discussion revolves around a static equilibrium problem involving force decomposition and torque calculations, as indicated by the original poster's reference to torque equations and trigonometric components.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses confusion regarding the trigonometric components in their torque equation, questioning the correctness of their understanding based on the provided diagram. Some participants suggest that using the perpendicular radius is key to resolving the trigonometric discrepancies.

Discussion Status

Participants are actively engaging with the problem, with some providing insights into the importance of the perpendicular radius in torque calculations. There is an acknowledgment of the need for clarity in the trigonometric relationships involved, but no consensus has been reached yet.

Contextual Notes

The original poster references a diagram for context, which is crucial for understanding the problem setup. There may be assumptions about the angles and forces that are currently under scrutiny.

Navyeel
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Homework Statement
I dont fully understand why the decompositions of forces.
Relevant Equations
F stands for friction, N is normalforce.
If you see the $\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$, all the trigonemetric parts are all opposite of what i can understand, given the angle as drawed in the Picture/url.

Please help me :)https://pasteboard.co/IiXr8qA.png
 
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I think I got it, my fault was that i forgot that in torque that if i use perpendicular radius i will get the cosines and the sinus parts correct :)
 
Yes it's always the perpendicular radius you need to use.

I note they are summing the torque about an axis at the top of the ladder.
 
Navyeel said:
If you see the $\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$
To get that LaTeX to render, you need doubled dollar signs like so:
$$\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$$
 
Ah ok, thanks :smile:
 

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