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brentwoodbc
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Homework Statement
A uniform 0.122 kg rod of 0.90 m length is used to suspend two masses as shown.
At what distance x should the 0.20 kg mass be placed to achieve static equilibrium?
2. The attempt at a solution
F1=1.96N
F2=4.9N
torque = 4.9 x 0.25 = 1.225 Nm.cw
1.23 = 1.96r
r=0.63m
answer is actually 0.5
I think its because of the force of 1.96 (0.20kg) being to the right of the end of the rod (which has a mass)
could someone please help me.
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