1. The problem statement, all variables and given/known data A uniform 0.122 kg rod of 0.90 m length is used to suspend two masses as shown. At what distance x should the 0.20 kg mass be placed to achieve static equilibrium? 2. The attempt at a solution F1=1.96N F2=4.9N torque = 4.9 x 0.25 = 1.225 Nm.cw 1.23 = 1.96r r=0.63m answer is actually 0.5 I think its because of the force of 1.96 (0.20kg) being to the right of the end of the rod (which has a mass) could someone please help me.