Static equilibrium of diving board

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 5K views
barz1
Messages
4
Reaction score
0

Homework Statement


A uniform diving board of mass=27kg and length x=4.3m is supported by two beams. beam A at x=0m and beam B at x=1.1m. A 68kg diver stands at the other side of the board.
A. Find force on support A.
B. Find force on support B.


Homework Equations


Net force = 0
Net torque = 0
md=68kg -mass of diver
mb=27kg - mass of board
l = 4.3m - length of board


The Attempt at a Solution


I am just having a lot of trouble figuring out the forces and toques for these static equilibrium problems. So I set my ForceNet = 0 = md*g + mb*g - FA - FB. (Not sure if this is correct)
TorqueNet = md*g*l + mb*g*(l/2) - FA*(0)? - FB*1.1
So I guess I don't understand what to use as my pivot point because this torque equation gets rid of my FA all together.

Thanks!
 
Physics news on Phys.org
barz1 said:

The Attempt at a Solution


I am just having a lot of trouble figuring out the forces and toques for these static equilibrium problems. So I set my ForceNet = 0 = md*g + mb*g - FA - FB. (Not sure if this is correct)

Yep that is correct.

barz1 said:
TorqueNet = md*g*l + mb*g*(l/2) - FA*(0)? - FB*1.1
So I guess I don't understand what to use as my pivot point because this torque equation gets rid of my FA all together.

What you did was take the sum of the torques about the point A, so this will give you FB

Remember, the sum of the torques about any point is zero.

So if you want FA, you can sum the torques about point B.