Static Equilibrium of pedestals

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SUMMARY

The discussion focuses on calculating the forces acting on a diving board supported by two pedestals when a diver weighing 730 N stands at the end. The board's length is 5 m, and the distance between the pedestals is 1.5 m. The equations established are based on static equilibrium, specifically the sum of forces in the vertical direction equating to zero. The user correctly identifies the forces from the left and right pedestals and sets up two equations to solve for the unknown forces.

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  • Understanding of static equilibrium principles
  • Knowledge of force diagrams and free-body diagrams
  • Familiarity with Newton's laws of motion
  • Basic algebra for solving equations
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  • Study the concept of torque and its application in static equilibrium
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Homework Statement


A diver of weight 730 N stands at the end of a diving board of length L = 5 m and negligible mass. The board is fixed to two pedestals separated by distance d = 1.5 m.

What are the magnitude and direction of the force on the board from the left pedestal? (Include the sign. Take upward to be positive.)


Homework Equations


I think that it's this..

sum of forces in the y direction = 0

force of left pedestal = Fl
force of right pedestal = Fr
force of diver = mg = 730N



The Attempt at a Solution



-Fl + Fr - mg = 0
3.5Fr(mg) - (0)mg = 5Fl(mg)

is this on the right track?
 
Physics news on Phys.org
Looks good! You have 2 equations with 2 unknowns so you can find the answer.
 

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