[static equilibrium] pin and link support type

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SUMMARY

This discussion clarifies the differences between pin and link supports in structural analysis. A pin support, such as at point A, provides two reaction force components (fx and fy), while a link support, like at point G, typically only provides one component (fx) due to its classification as a '2-force' member. The distinction arises because 2-force members can only support axial loads along their longitudinal axis, resulting in horizontal reactions at certain joints. Understanding these concepts is crucial for analyzing structures effectively.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with structural analysis terminology
  • Knowledge of 2-force member behavior in trusses
  • Basic concepts of reaction forces in mechanics
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  • Study the mechanics of 2-force members in truss structures
  • Learn about the implications of axial loading in structural members
  • Explore the differences between various types of supports in structural engineering
  • Investigate the application of equilibrium equations in analyzing static structures
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Structural engineers, civil engineering students, and anyone involved in analyzing or designing frameworks and trusses will benefit from this discussion.

kougou
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Hello every one

I am confused between two support type:
the pin, and the link

On the textbook, it says, the pin prevents the object from translating vertically and horzontally, therefore, it provides fx and fy reaction forces.

but another type of support is much identical to the pin, which is the link support, the photo is here: http://imageshack.us/f/105/pinconnectiontw4.jpg/

at point A, the beam AB is subjected to the pin support, so it has two components of reaction forces, namely fx and fy

but what about at point G, how come it only provides one force components, namely fx, but not fy as well? is the point G also classified as pin support?
i am very confused; instructor said that whenever u see a pin support, there's two force components; how come this is not a case here?
 
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is the link support the beam which connects from GB, and pin support the node at G and A?
 


G is a pinned support as well as A. The reason there is reaction in x only at G is because member GB can support axial loads only.
 
kougou said:
Hello every one

I am confused between two support type:
the pin, and the link

On the textbook, it says, the pin prevents the object from translating vertically and horzontally, therefore, it provides fx and fy reaction forces.

but another type of support is much identical to the pin, which is the link support, the photo is here: http://imageshack.us/f/105/pinconnectiontw4.jpg/

at point A, the beam AB is subjected to the pin support, so it has two components of reaction forces, namely fx and fy

but what about at point G, how come it only provides one force components, namely fx, but not fy as well? is the point G also classified as pin support?
i am very confused; instructor said that whenever u see a pin support, there's two force components; how come this is not a case here?
Yes, point G is a pin support. In general, there are 2 force components at a pin, in the x and y direction, but in some cases, such as joint G, there is only one. This is due to equilibrium considerations for so called '2-force' members. A 2-force member is a member subjected to a force (applied or a reaction force) at each end with no forces applied in between. All members of a truss are 2 force members when loads are applied at the joints only. Member BG is a 2-force member. As such, it can only take axial loading in tension or compression along its longitudinal axis. Thus , the reaction at G must be entirely horizontal; otherwise, the resultant reaction force could not be directed along the BG axis.

EDIT: I notice you are posting the same question in the ME sub-forum. You should stick to that forum and communicate further with the responder if you have additional questions.
 
Last edited:
PhanthomJay said:
Yes, point G is a pin support. In general, there are 2 force components at a pin, in the x and y direction, but in some cases, such as joint G, there is only one. This is due to equilibrium considerations for so called '2-force' members. A 2-force member is a member subjected to a force (applied or a reaction force) at each end with no forces applied in between. All members of a truss are 2 force members when loads are applied at the joints only. Member BG is a 2-force member. As such, it can only take axial loading in tension or compression along its longitudinal axis. Thus , the reaction at G must be entirely horizontal; otherwise, the resultant reaction force could not be directed along the BG axis.

EDIT: I notice you are posting the same question in the ME sub-forum. You should stick to that forum and communicate further with the responder if you have additional questions.

apologize, this is my first time to use this forum... . I will never do that again.

and what about this http://www.ecourses.ou.edu/cgi-bin/view_anime.cgi?file=512LIN.swf&course=st&chap_sec=05.1, the link support, which is very similar to the pin support? Same reasoning as well?
 
kougou said:
apologize, this is my first time to use this forum... . I will never do that again.

and what about this http://www.ecourses.ou.edu/cgi-bin/view_anime.cgi?file=512LIN.swf&course=st&chap_sec=05.1, the link support, which is very similar to the pin support? Same reasoning as well?
Welcome to Physics forums, kougou! Yes, same reasoning for a link support; the support reactions are always directed along the longitudinal axis of the member, creating only tension or compression axial forces in the member, regardless of the angle of the link, provided that there are no forces applied in between the 2 ends. NOTE that when the link is at an angle, there are still x and y components of the link reaction forces, but their resultant sum is a single force directed axially along the link, no bending or shear stresses.
 
I have encountered a vertically oriented hydraulic cylinder that is designed to actuate and slice heavy cabling into sections with a blade. The cylinder is quite small (around 1.5 inches in diameter) and has an equally small stroke. The cylinder is single acting (i.e. it is pressurized from the bottom, and vented to atmosphere with a spring return, roughly 200lbs of force on the spring). The system operates at roughly 2500 psi. Interestingly, the cylinder has a pin that passes through its...

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