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## Homework Statement:

- The boom in the figure below weighs 3100 N and is attached to a frictionless pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 35.0 % of its length.

## Relevant Equations:

- $$\sum\vec F=\vec0\\\sim\vec\tau=\vec0$$

I will also have ##w_x=w\sin\frac{\pi}{6}\cos\frac{\pi}{6}=\frac{\sqrt 3}{4}w## and ##w_y=w\sin\frac{\pi}{6}\sin\frac{\pi}{6}=\frac 14w##.

$$\sum F_y=5000+w_y-R_y=5000+\frac 14w-\frac 34w=0\\w=10000\,N

\\\sum F_x=T-R_x-w_x=T-\frac{\sqrt3}{4}w-\frac{\sqrt 3}{4}w=0\\T=5000\sqrt3\,N$$

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