Static Friction on an Inclined Plane: Force = mgsin30

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SUMMARY

The discussion centers on the static friction force acting on a block of mass m resting on an inclined plane at a 30º angle. The correct relationship is established as fs = mgsin30º, confirming that the force of static friction equals the component of gravitational force acting parallel to the incline. Participants agree that option D is the accurate statement regarding static friction in this scenario.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of static friction
  • Familiarity with inclined planes in physics
  • Ability to perform trigonometric calculations
NEXT STEPS
  • Study the concept of static versus kinetic friction
  • Explore the effects of different angles on static friction
  • Learn about the role of mass in frictional forces
  • Investigate applications of inclined planes in real-world scenarios
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Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of static friction on inclined planes.

StephenDoty
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A block of mass m is at rest on an inclined plane that makes an angle of 30º with the
horizontal, as shown in the figure. Which of the following statements about the force of
static friction is true?
A) fs > mg D)fs = mg sin 30º
B) fs > mg cos 30º E) None of these statements is true.
C) fs = mg cos 30º

because the only two forces acting on the block is fs and weight, F=0 since at rest, thus 0=fs - mgsin30 so
fs= mgsin30


So the answer is D right??
 
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