Statics problem. Is my work correct?

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SUMMARY

The discussion centers on solving a statics problem involving a pulley system and the correct identification of forces acting on it. The key equations used are ƩF=0 and ƩM=0. The participant initially misidentified the free body diagram (FBD) by omitting the internal horizontal cable tension acting on the pulley, which led to incorrect calculations. After addressing this oversight, the participant successfully recalculated the forces, concluding that the horizontal reaction force Ex equals 0.

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Homework Statement



2u7m8mf.jpg


Homework Equations



ƩF=0
ƩM=0

The Attempt at a Solution



I have done parts 1-3 (parts 1-2 in image) and I think it's right. It's been a while since I've had statics and I'm not 100% sure it's right. For part 4, where the pulley meets the frame at F do I need a Fx and Fy? or Fx ,Fy, and MF?

fvwtif.jpg
 
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Your initial FBD of the system (the whole frame) is not correct. You seem to have cut the rope and identified the internal horizontal cable tension as 500 N to the right at C, but you left off the internal horizontal cable tension of 500 N that acts to the left at the top of the pulley.
Don't cut the rope yet, and focus instead on the whole system and identify the external forces acting on it. The external forces are the applied vertical load of 500 N down on the rope, and the reaction forces at A and E. The horizontal cable tension is internal to the system and thus is not an external force, so it does not come into play when looking at the FBD of the system. Now sum moments and forces equal to 0. You will find perhaps a surprising result for the reaction at E.
 
PhanthomJay said:
Your initial FBD of the system (the whole frame) is not correct. You seem to have cut the rope and identified the internal horizontal cable tension as 500 N to the right at C, but you left off the internal horizontal cable tension of 500 N that acts to the left at the top of the pulley.
Don't cut the rope yet, and focus instead on the whole system and identify the external forces acting on it. The external forces are the applied vertical load of 500 N down on the rope, and the reaction forces at A and E. The horizontal cable tension is internal to the system and thus is not an external force, so it does not come into play when looking at the FBD of the system. Now sum moments and forces equal to 0. You will find perhaps a surprising result for the reaction at E.

Yes, I did figure it out. I left out the force to the left on top of the pulley. That gave me new answers. Ex turned out to equal 0.

Thanks for the help.
 

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