Statics Question: Finding Unknown Displacement on a Spring with 175N Force

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The discussion revolves around calculating the displacement of a spring under a 175N force using the equation F=kx. The user initially assumes that the force is evenly distributed, resulting in 87.5N opposing forces at each end of the spring. They calculate the displacement to be 0.175m but express confusion about the accuracy of this result. Another participant suggests analyzing the components of the forces, emphasizing the absence of horizontal forces. The conversation highlights the importance of understanding force distribution and tension in the springs.
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Homework Statement


HW2PG1-1.jpg

#16

Homework Equations


F=kx
and sum of all the vertical and horizontal forces each has to = 0

The Attempt at a Solution


Because each end of the spring is like a pin it has an opposing force of 175/2 N on each end to balance out the 175N being pulled in the middle.
So I took at force and put it in the f=kx equation and solved for x. Which I got to be .175m but i don't see why I did made sense, but i have no idea how to begin this
 
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kyin01 said:
Because each end of the spring is like a pin it has an opposing force of 175/2 N on each end to balance out the 175N being pulled in the middle.
So I took at force and put it in the f=kx equation and solved for x. Which I got to be .175m but i don't see why I did made sense, but i have no idea how to begin this

Hi kyin01! :smile:

Begin by calling the distance from the wall x, and taking components. :wink:
 
tiny-tim said:
Hi kyin01! :smile:

Begin by calling the distance from the wall x, and taking components. :wink:

ok i did that, there are no horizontal forces (and by horizontal i mean forces parallel with the wall).

As for vertical forces I found them to be 87.5 on each side of the pin opposing the direction of the pulling force
 
kyin01 said:
ok i did that, there are no horizontal forces (and by horizontal i mean forces parallel with the wall).

As for vertical forces I found them to be 87.5 on each side of the pin opposing the direction of the pulling force

ok … so what's the tension in each spring? :smile:
 

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