Statics Question (Using Modulus of Rigidity)

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The discussion revolves around calculating the horizontal displacement at point A due to a force P using the modulus of rigidity. Participants are debating whether to use a single G value for the top layer or to account for multiple layers in their calculations. One user outlines their method of calculating shear stress and strain, but is uncertain about the correct height to use in their equations. They express frustration over consistently obtaining results that are slightly off, questioning the accuracy of their approach. The conversation highlights the importance of considering all layers and the correct parameters in statics problems.
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Homework Statement



Find the displacement (mm) in the horizontal direction of point A due to the force, P. P=100kN w1=19mm w2=15mm

Homework Equations



\tau = G * \gamma
\tau = Shear stress = P / A
\gamma = Shear strain = (pi / 2) - \alpha

The Attempt at a Solution



I haven't attempted to work out a solution here yet, but I do have a question regarding the separate G values that are given.

Can I just look at the top layer, the layer where P is acting, and use that G value to determine \delta? Or do I need to do something with the other G value as well?

If I were to try something, I would find tau by doing 100[kN] / (100[mm] * 2[mm]). So tau would be equal to 1[kN]/2[mm2] = 0.5[GPa]. Next I would find gamma by dividing tau by G (100[GPa]) giving me \gamma = .005rad. I can use trig to define gamme as \gamma=sin-1(\delta/40). Setting this equal to .005 I would get \delta= .20[mm].

Even if I do have to do something with both of the G values, I feel like my method is correct. Any help is appreciated, thanks in advance.
 

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Hi papasmurf
 
Last edited:
If delta at A is relative to the fixed base, then all the shear displacements of the various layers must be taken into account.
 
Am I correct in assuming the shear force will be the same at all the various layers?
 
Hi Dr.PSMokashi
 
I'm getting closer to the correct answer. First I set V/A, where V is the internal shear force and A is the area of the cross section where the shear force is acting, equal to G*\gamma, where G is the modulus of rigidity and gamma is the shear strain.
I rewrote gamma as pi/2 - θ, where θ=cos-1(\delta/h), h is the height of the "layer", and put it all together so that my equation looks like this:

V/A = G * ( pi/2 - cos-1(\delta/h) )

Solving for \delta I come up with
\delta = h * cos( (pi/2) - V/AG)

I used this formula for each "layer" and added up all of the deltas.

However after plugging my numbers in and making sure of correct units, I still am off by fractions of a millimeter.
 
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Also, should the h value be the height of the layer only or should it go from the base to the top of the layer I am looking at? For example if I am looking at the first layer where G=0.1MPa, would my h be simply w2 [mm] or would it be w2+2 [mm]?
 
I keep getting an answer that is off by fractions of a millimeter. I can not figure out what I am doing/not doing that keeps giving me a wrong answer.
 
How do you know that "an answer that is off by fractions of a millimeter" is "a wrong answer"?
 

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