papasmurf
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Homework Statement
Find the displacement (mm) in the horizontal direction of point A due to the force, P. P=100kN w1=19mm w2=15mm
Homework Equations
\tau = G * \gamma
\tau = Shear stress = P / A
\gamma = Shear strain = (pi / 2) - \alpha
The Attempt at a Solution
I haven't attempted to work out a solution here yet, but I do have a question regarding the separate G values that are given.
Can I just look at the top layer, the layer where P is acting, and use that G value to determine \delta? Or do I need to do something with the other G value as well?
If I were to try something, I would find tau by doing 100[kN] / (100[mm] * 2[mm]). So tau would be equal to 1[kN]/2[mm2] = 0.5[GPa]. Next I would find gamma by dividing tau by G (100[GPa]) giving me \gamma = .005rad. I can use trig to define gamme as \gamma=sin-1(\delta/40). Setting this equal to .005 I would get \delta= .20[mm].
Even if I do have to do something with both of the G values, I feel like my method is correct. Any help is appreciated, thanks in advance.
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