Statics Shear Force and Bending Moment Diagrams Problem

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Discussion Overview

The discussion revolves around a statics problem involving the calculation of shear force and bending moment diagrams. Participants are addressing the reactions at specific points on a beam and the implications for equilibrium.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant claims to have resolved the problem but does not provide details.
  • Another participant emphasizes the necessity of calculating reactions at points C and E to construct the shear and moment diagrams.
  • A participant explains their calculations, stating that the horizontal reaction at C is zero due to the absence of forces in the x direction, and provides a value for the vertical reaction at E.
  • Another participant challenges the assumption of zero reaction at C, arguing that the beam cannot be in equilibrium with a reaction at E and zero at C due to the presence of a net moment around C.

Areas of Agreement / Disagreement

Participants express disagreement regarding the reactions at points C and E, with no consensus on the correct approach to achieving equilibrium.

Contextual Notes

Participants have not fully resolved the assumptions regarding the forces acting on the beam, particularly the implications of having no reactions at C.

jordan35
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Figured it out.
 

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For one thing, you haven't calculated the reactions at C and E. Until you do, you won't be able to construct the shear and moment diagrams.

If I am interpreting what you posted correctly, you have all of your reaction at E and none at C. Why?
 
Cx= 0 b/c there are no other forces in the x direction. Ey = 2.43 from sum of moments, and Cy = 0 after plugging into sum of the forces in the y direction. I thought this was strange to have no reactions at C, but don't know what I could have messed up with that part.
 
Sorry, but if you take the reaction at E = 2.43 kN and a zero reaction at C, the beam is NOT in equilibrium because there is a net moment around C.
 

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