For problems 102 and 103, find the value of Mc required to maintain equilibrium, and find the forces at C. Ma is given as 20 Nm for both problems. [/B]
Start with AB. The geometry is a 3/4/5 triangle, so AB is 100mm or 0.1 M.
B=20/0.1 or 200N
So the force at B has to be 200N at the 53.1-degree angle dictated by the geometry.
The Attempt at a Solution
I found, online, a solution to problem 103; the parameters are different but I understand the logic given for problem 103.
I see the subtle difference between 102 and 103: in 103, the collar can only move along AB, and in 102, the collar can only move along CB.
For problem 102, the book's answer is Cx = 217N.
Intuitively, this makes no sense.
How can Cx be more than the 200N force at B? The force at B, which is 200N, would be the hypotenuse of a triangle that would intersect Cx and Cy. So Cx would have to be smaller than 200N.
Is the 200N force at B not correct for problem 102?
Thank you in advance for any insight! :^)
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