Steam = 100C -- how much steam got injected into the water to heat it up?

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SUMMARY

The discussion focuses on calculating the heat transfer involved when steam at 100°C is injected into water. The primary equation used is Q = c * m * (t2 - t1), where Q represents heat, c is the specific heat capacity, m is the mass, and t2 and t1 are the final and initial temperatures, respectively. Participants emphasize the importance of establishing a heat balance, stating that the heat given off by the steam must equal the heat absorbed by the water. The discussion also references the principles of steam engineering as outlined on Spirax Sarco's website.

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Yeahaight
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Homework Statement
To heat 4 kg of water from 10 C to 90 C, 100 C water vapor was injected. How much steam was injected?
Given values:
m1 = 4kg
t1 = 10 C
t2 = 90 C
t = 100 C
c water = 4,2*10^3 J/kg*k
r = 22,6*10^5 J/K
Relevant Equations
Q = r*m
Q = c*m(t2-t1)
I guess, firstly I have to calculate the heat that is needed.
Q=c*m(t2-t1)
I'm not sure what to do further from here.
 
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Yeahaight said:
I'm not sure what to do further from here
You set up a heat balance: heat given off = heat taken up
 
BvU said:
You set up a heat balance: heat given off = heat taken up
Well, heat taken up would be - Q = c water*m1*(t2-t1)?
I'm not sure about heat given off, though.
 
What is the definition of r?
 
Yeahaight said:
I'm not sure about heat given off, though
So you want to find out how much heat is given off by starting out with x kilograms of water vapour at 100 ##^\circ##C and ending up with ... ?

How do you combine your relevant equations to describe this process ?
 
I have deleted some posts. Please do not provide a full solution, but instead help the OP do the work.
 
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