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u_k = 0.6

Components:

F_y:

n - mg = 0

n= mg

F_x:

F_t - u_kn = ma_x

F_t - u_kmg = ma_x

4.0N - (.6)(.5kg)(9.8m/s^2) = ma_x

4.0N - 2.94N = ma_x

1.06N / .5kg = a_x

a_x = 2.12m/s^2

I found the acceleration of the block, now I need to find the speed at which the tube breaks....

F = ma = (mv^2 / r)

v^2 = (Fr / m)

v = SqRt [(50N)(1.2m) / .5kg ]

v= 10.95m/s

Now do I use a kinematic equation to find distance?

v_f^2 = v_i^2 + 2a(deltaD)

(10.95m/s)^2 = 0 +2(2.12m/s^2) D

D= 10.95 / 4.24

D= 2.58 m

Now this is where I get stuck. If I have done everything correctly up to this point, which I am not sure if I have (correct me if it's wrong), how do I put everything together? What equation do I use?

Any help would be great!!