MHB Stephanie's question at Yahoo Answers (Domain question)

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The function f(x) = 1 / (4 / ((x-1) - 2)) simplifies to f(x) = (x-1) / (6-2x) for x ≠ 1. The function is undefined at x = 1 and x = 3, leading to the domain being all real numbers except these two values. To find the value of 1 in the context of the function, it is important to understand the restrictions on x that affect the function's definition. This mathematical explanation clarifies how to approach similar domain questions. The discussion emphasizes the importance of identifying points where the function is undefined.
Fernando Revilla
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Here is the question:

f(x) = (1) / (4 / ((x-1) - 2))

I got the 3 but I can not get the 1.

Can you possibly tell me what this would be called so I can google it, and if possible explain mathematically how to get the 1; besides substituting in numbers?

Here is a link to the question:

Math Help - Domain Question? - Yahoo! Answers

I have posted a link there to this topic, so the OP can find my response.
 
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Re: Stepanie's question at Yahoo! Answers (Domain question)

Hello Stephanie,

The funcion is $f(x)=\dfrac{1}{\dfrac{4}{x-1}-2}$. But $\dfrac{4}{x-1}$ is defined if and only if $x\neq 1$ so, $$f(x)=\dfrac{1}{\dfrac{4-2x+2}{x-1}}=\dfrac{x-1}{6-2x}\quad (\mbox{if }x\neq 1)$$ For $x\neq 1$, $f(x)$ is defined if and only if $x\neq 3$. Hence, $\mbox{Dom } f=\mathbb{R}-\{1,3\}$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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