Stephanie's question at Yahoo Answers (Domain question)

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SUMMARY

The function in question is defined as f(x) = 1 / (4 / (x - 1) - 2). The critical points for this function occur at x = 1 and x = 3, where the function is undefined. The domain of f(x) is therefore all real numbers except for these two points, expressed as Dom f = ℝ - {1, 3}. This conclusion allows for a clear understanding of the function's limitations and behavior.

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Here is the question:

f(x) = (1) / (4 / ((x-1) - 2))

I got the 3 but I can not get the 1.

Can you possibly tell me what this would be called so I can google it, and if possible explain mathematically how to get the 1; besides substituting in numbers?

Here is a link to the question:

Math Help - Domain Question? - Yahoo! Answers

I have posted a link there to this topic, so the OP can find my response.
 
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Re: Stepanie's question at Yahoo! Answers (Domain question)

Hello Stephanie,

The funcion is $f(x)=\dfrac{1}{\dfrac{4}{x-1}-2}$. But $\dfrac{4}{x-1}$ is defined if and only if $x\neq 1$ so, $$f(x)=\dfrac{1}{\dfrac{4-2x+2}{x-1}}=\dfrac{x-1}{6-2x}\quad (\mbox{if }x\neq 1)$$ For $x\neq 1$, $f(x)$ is defined if and only if $x\neq 3$. Hence, $\mbox{Dom } f=\mathbb{R}-\{1,3\}$
 

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